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pokemon23

  • 4 years ago

Factor again the expression

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  1. pokemon23
    • 4 years ago
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    |dw:1328232397824:dw|

  2. pokemon23
    • 4 years ago
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    |dw:1328232408765:dw|

  3. anonymous
    • 4 years ago
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    8x-12 gcf(8x, -12) = 2 2(4x-6) yep

  4. anonymous
    • 4 years ago
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    no

  5. anonymous
    • 4 years ago
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    you can factor one more time

  6. pokemon23
    • 4 years ago
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    you can?

  7. anonymous
    • 4 years ago
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    yes, 4=2*2 6=2*3

  8. pokemon23
    • 4 years ago
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    so how will this change the problem?

  9. anonymous
    • 4 years ago
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    you can factor 2 again?

  10. pokemon23
    • 4 years ago
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    so the answer can be rewritten?

  11. anonymous
    • 4 years ago
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    yes

  12. pokemon23
    • 4 years ago
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    so its |dw:1328232744159:dw|

  13. anonymous
    • 4 years ago
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    so you can get 2 out of brackets again

  14. Mertsj
    • 4 years ago
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    The greatest common factor of 8x and 12 is 4 so factor out a 4

  15. Mertsj
    • 4 years ago
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    \[8x-12=4(2x-3)\]

  16. anonymous
    • 4 years ago
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    no. you've got to no that when you take out a number you divide by it and take it out! Take that two out and put it with the other 2 and get 4 4(x-3)

  17. anonymous
    • 4 years ago
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    4(2x-3)

  18. pokemon23
    • 4 years ago
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    |dw:1328233073865:dw|

  19. anonymous
    • 4 years ago
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    you can divide by 3x because that is the biggest thing they have in common

  20. anonymous
    • 4 years ago
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    3x(x-2)

  21. pokemon23
    • 4 years ago
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    |dw:1328233197459:dw|

  22. pokemon23
    • 4 years ago
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    |dw:1328233208300:dw|

  23. anonymous
    • 4 years ago
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    It is not simplified, you still have an x in common, so divide by x and take the x out by the 2

  24. anonymous
    • 4 years ago
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    2x(1-2x^2)

  25. pokemon23
    • 4 years ago
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    I see

  26. pokemon23
    • 4 years ago
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    |dw:1328233484451:dw|

  27. pokemon23
    • 4 years ago
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    |dw:1328233511015:dw|

  28. anonymous
    • 4 years ago
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    it still has something in common?

  29. pokemon23
    • 4 years ago
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    |dw:1328233660048:dw|

  30. pokemon23
    • 4 years ago
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    how about now?

  31. anonymous
    • 4 years ago
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    right

  32. pokemon23
    • 4 years ago
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    yes :D

  33. pokemon23
    • 4 years ago
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    ty that is all ym hw help :D thanks for everything and Thomas and Mert

  34. anonymous
    • 4 years ago
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    You're welcome

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