A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

Does anyone know how to do a problem by completing the square? I'm so confused.

  • This Question is Closed
  1. Mertsj
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    We all do.

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes, we do

  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but best to work with a specific example

  4. Mertsj
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Even the Great Satellite stands ready to help you.

  5. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    example: 4x^2 + 8x + 1 Using a^2 + 2ab + b^2 = (a + b)^2, we have (2x + 1)^2 There's other formulas.

  6. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    like a^2 - 2ab + b^2 = (a - b)^2

  7. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    example:3x²-6x-9=0

  8. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    step number one is to divide by three and get \[x^2-2x-3=0\] then add 3 to both sides and get \[x^2-2x=3\] and now we are ready to "complete the square" although we can also solve this one by factoring

  9. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    half of -2 is -1 and \[(-1)^2=1\] so you can write \[x^2-2x=3\] and then \[(x-1)^2=3+1=4\] the last step was adding 1 to both sides so that the left hand side is now a perfect square

  10. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then solve as \[(x-1)^2=4\] \[x-1=2\] or \[x-1=-2\] so \[x=3\] or \[x=-1\]

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.