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anonymous
 4 years ago
7 females, and 5 males including Larry.
There are 4 tasks to be assigned. Note that assigning the same
people different tasks constitutes a different assignment.
(1) Find the probability that both males and females are given a task.
(2) Find the probability that Larry and at least one female
are given tasks.
anonymous
 4 years ago
7 females, and 5 males including Larry. There are 4 tasks to be assigned. Note that assigning the same people different tasks constitutes a different assignment. (1) Find the probability that both males and females are given a task. (2) Find the probability that Larry and at least one female are given tasks.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow check this out http://www.jiskha.com/display.cgi?id=1236051521

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0larry must be a popular guy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0these word problems are killing me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is the same problem with different numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I had to take an exam today. And this homework set is due on tomorrow at 730 am. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02 days to complete them

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I like to know what i am doing though

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Wyatt Earp: Speed is great but accuracy is everything.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am always mixing these up as I work through them

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have 12 or 13 problems due in the morning

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I feel like a math bum :)

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Don't feel. Just work. Post the other 12 or 13 problems individually on this site. You do that while I work on this problem. I may have to stop and eat some brain food. :} You need to focus. Nobody here is a bum.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that the final solution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for both male and female

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know I am very lost haha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why the zero in both combinations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not quite brain food :) and this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ha ha i post them wuickly

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1P(both genders) = 1  { [ C(7,0) C(5,4)  C(7,4) C(5,0)] / C(12,4) } = 1  40/495 = 455/495 = 91/99 = .919 approx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So the second part would be similar?

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1P(Larry and at least 1 F) P(at least 1F) = 1  P(0F) = 1 { [C(7,0)C(5,4)] } / C(12,4) = 5/495 = 490/495 = 98/99 = .99 ish. Ways to choose Larry = 1 C(1,1) = 1 P(Larry and at least 1 F) = 1(98/99) = 98/99 = .99 approx

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1But, we want Larry and none of the other males. So P(Larry) = C(1,1) C(4,0) = 1. That would be Larry and none of the other males.

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1I'm going to cases for this. Slow but may make more sense.

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Larry and at least 1F  Cases {Lar, 1F, 2 other M}; {Lar, 2F, 1 other M}; and {Lar, 3F, 0 other M}

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Ways to choose Lar, 1F, 2 other M} = 1 C(7,1) C(4,2) = 42 Ways to choose {Lar, 2F, 1 other M}; = 1 C(7,2) C(4,1)= 84 Ways to choose {Lar, 3F, 0 other M} = 1 C(7,3) C(4,0) = 35 Ways to choose 4 from 12 is C(12,4) = 495 P(L and at least 1F) = [42 + 84 +35] / 495 = 161/495 =.325 approx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0CORRECT! You are a genius.... I have posted some more. I haven't wanted to post to many at a time and flood the screen

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am wrong no matter what i do on these

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Let's find another problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I used a lot of the work i learned from hear that helped me on the test in some of these.
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