anonymous
  • anonymous
7 females, and 5 males including Larry. There are 4 tasks to be assigned. Note that assigning the same people different tasks constitutes a different assignment. (1) Find the probability that both males and females are given a task. (2) Find the probability that Larry and at least one female are given tasks.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Directrix
  • Directrix
Hey, CW.
anonymous
  • anonymous
hey
anonymous
  • anonymous
wow check this out http://www.jiskha.com/display.cgi?id=1236051521

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
larry must be a popular guy
anonymous
  • anonymous
how ya doin g
anonymous
  • anonymous
doing
anonymous
  • anonymous
these word problems are killing me
anonymous
  • anonymous
it is the same problem with different numbers
anonymous
  • anonymous
I had to take an exam today. And this homework set is due on tomorrow at 730 am. :)
anonymous
  • anonymous
2 days to complete them
anonymous
  • anonymous
no i am not....
anonymous
  • anonymous
I like to know what i am doing though
Directrix
  • Directrix
Wyatt Earp: Speed is great but accuracy is everything.
anonymous
  • anonymous
exactly
anonymous
  • anonymous
i am always mixing these up as I work through them
anonymous
  • anonymous
I have 12 or 13 problems due in the morning
anonymous
  • anonymous
I feel like a math bum :)
Directrix
  • Directrix
Don't feel. Just work. Post the other 12 or 13 problems individually on this site. You do that while I work on this problem. I may have to stop and eat some brain food. :} You need to focus. Nobody here is a bum.
anonymous
  • anonymous
is that the final solution
anonymous
  • anonymous
for both male and female
anonymous
  • anonymous
i know I am very lost haha
anonymous
  • anonymous
it didnt work though
anonymous
  • anonymous
why the zero in both combinations
anonymous
  • anonymous
not quite brain food :) and this one
anonymous
  • anonymous
ha ha i post them wuickly
anonymous
  • anonymous
quickly
Directrix
  • Directrix
P(both genders) = 1 - { [ C(7,0) C(5,4) - C(7,4) C(5,0)] / C(12,4) } = 1 - 40/495 = 455/495 = 91/99 = .919 approx
anonymous
  • anonymous
Correct
anonymous
  • anonymous
So the second part would be similar?
Directrix
  • Directrix
P(Larry and at least 1 F) P(at least 1F) = 1 - P(0F) = 1 -{ [C(7,0)C(5,4)] } / C(12,4) = 5/495 = 490/495 = 98/99 = .99 ish. Ways to choose Larry = 1 C(1,1) = 1 P(Larry and at least 1 F) = 1(98/99) = 98/99 = .99 approx
anonymous
  • anonymous
no it didnt work
anonymous
  • anonymous
larry wouldnt be 5?
anonymous
  • anonymous
5,1
Directrix
  • Directrix
But, we want Larry and none of the other males. So P(Larry) = C(1,1) C(4,0) = 1. That would be Larry and none of the other males.
Directrix
  • Directrix
I'm going to cases for this. Slow but may make more sense.
anonymous
  • anonymous
how ya doing
Directrix
  • Directrix
Larry and at least 1F -------- Cases {Lar, 1F, 2 other M}; {Lar, 2F, 1 other M}; and {Lar, 3F, 0 other M}
Directrix
  • Directrix
Ways to choose Lar, 1F, 2 other M} = 1 C(7,1) C(4,2) = 42 Ways to choose {Lar, 2F, 1 other M}; = 1 C(7,2) C(4,1)= 84 Ways to choose {Lar, 3F, 0 other M} = 1 C(7,3) C(4,0) = 35 Ways to choose 4 from 12 is C(12,4) = 495 P(L and at least 1F) = [42 + 84 +35] / 495 = 161/495 =.325 approx
anonymous
  • anonymous
CORRECT! You are a genius.... I have posted some more. I haven't wanted to post to many at a time and flood the screen
anonymous
  • anonymous
I am wrong no matter what i do on these
Directrix
  • Directrix
Let's find another problem.
anonymous
  • anonymous
I used a lot of the work i learned from hear that helped me on the test in some of these.

Looking for something else?

Not the answer you are looking for? Search for more explanations.