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anonymous
 4 years ago
Find the average rate of change of f from 0 to 7pi/12.
f(x)=tan(2x)
anonymous
 4 years ago
Find the average rate of change of f from 0 to 7pi/12. f(x)=tan(2x)

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\tan(2 \cdot \frac{ 7 \pi}{12})\tan(2 \cdot 0)}{\frac{7 \pi }{12}0}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1let me find out by simplifying this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes it is correct, since it starts at (0,0)

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\tan(\frac{7 \pi}{6})}{\frac{7 \pi}{12}}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{12}{7 \pi} \cdot \tan(\frac{ 7 \pi}{6} )\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops i was wrong \[\tan(\frac{7\pi}{6})=\frac{1}{\sqrt{3}}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{12}{7 \pi} \cdot \frac{\sin(\frac{7 \pi}{6})}{\cos(\frac{7 \pi}{6})}\] \[\frac{12}{7 \pi} \cdot \frac{\sin( \pi +\frac{\pi}{6})}{\cos( \pi +\frac{\pi}{6})}\] \[\frac{12}{ 7 \pi} \cdot \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}=\frac{12}{7 \pi} \cdot \frac{1}{\sqrt{3}}\] lol sorry i was having a find an error in my latex
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