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Mathhelp346

  • 4 years ago

A bearing for a new sports car must be manufactured within 0.001 mm of its circumference of 2.35 mm. Write and solve an absolute value inequality to describe the largest and the smallest possible circumference for the bearing.

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  1. TuringTest
    • 4 years ago
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    how about if I wrote this: 'the distance between the actual size of the bearing and the perfect size of the bearing must be no more than x' ? that is very similar to the last statement you had

  2. Mathhelp346
    • 4 years ago
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    ?

  3. TuringTest
    • 4 years ago
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    let the actual size be b let the optimal size be a let the limit of error be x 'the distance between a and b must be no more than x' can you write that as you did the other? what are a and x ?

  4. Mathhelp346
    • 4 years ago
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    is a 0.001 and b 2.35

  5. TuringTest
    • 4 years ago
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    I called the limit of error x, so x=0.001 a would be the optimal measurement the actual measurement 'b' will be the variable 'A bearing for a new sports car must be manufactured within 0.001 mm of its circumference of 2.35 mm' = 'the distance between a and b must be no more than x' 'no more than' means 'less-than or equal-to', so we have \[|a-b|\le x\]\[|2.53-b|\le 0.001\]solve for b

  6. TuringTest
    • 4 years ago
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    typo above*\[|2.35-b|=0.001\]

  7. Mathhelp346
    • 4 years ago
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    ? why is it =?

  8. Mathhelp346
    • 4 years ago
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    shouldnt it be <

  9. TuringTest
    • 4 years ago
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    sorry another typo!

  10. Mathhelp346
    • 4 years ago
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    lol

  11. TuringTest
    • 4 years ago
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    \[|2.35-b|\le0.001\]or maybe\[|2.35-b|<0.001\]not really clear...

  12. Mathhelp346
    • 4 years ago
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    why is 0.001 there?

  13. TuringTest
    • 4 years ago
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    that is the maximum error in measurement like I said it is like saying 'the distance between the actual measurement and the optimal measurement (2.35) must be no more than 0.001' treat these as points on a number line as before:\[|2.35-b|\le0.001\]

  14. Mathhelp346
    • 4 years ago
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    oh ok i get it

  15. TuringTest
    • 4 years ago
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    |dw:1328239501252:dw|

  16. Mathhelp346
    • 4 years ago
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    ok

  17. TuringTest
    • 4 years ago
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    b can be any point on that shaded part|dw:1328239612650:dw|so we can write\[|a-b|\le x\]

  18. Mathhelp346
    • 4 years ago
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    ok

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