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anonymous

  • 4 years ago

At x = 2, (dy)/(dx) =

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  1. UnkleRhaukus
    • 4 years ago
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    what is the formula for y

  2. dumbcow
    • 4 years ago
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    depends on what y(x) is ??

  3. anonymous
    • 4 years ago
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    here was the first part Let y= 6 x^5 - 9. Find A, B, and C so that (dy)/(dx) = Ax^B +C

  4. anonymous
    • 4 years ago
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    A = 30 B = 4. C =0

  5. dumbcow
    • 4 years ago
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    use power rule dy/dx = 30x^4

  6. UnkleRhaukus
    • 4 years ago
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    \[y(x)=6x^5-9\] \[{dy(x) \over dx} =30x^4\] \[{dy(2) \over dx} =30 \times 2^4=30 \times 16=480\]

  7. anonymous
    • 4 years ago
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    thank you very much

  8. anonymous
    • 4 years ago
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    I was stuck

  9. UnkleRhaukus
    • 4 years ago
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    thinking about our answer to see if it makes sense, 480 is a big number , if that is our gradient at that point it is very steep but our equation for y is proportional to x^4 which gets large very quickly, so it makes sense that the slope is so steep

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