At x = 2, (dy)/(dx) =

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At x = 2, (dy)/(dx) =

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what is the formula for y
depends on what y(x) is ??
here was the first part Let y= 6 x^5 - 9. Find A, B, and C so that (dy)/(dx) = Ax^B +C

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A = 30 B = 4. C =0
use power rule dy/dx = 30x^4
\[y(x)=6x^5-9\] \[{dy(x) \over dx} =30x^4\] \[{dy(2) \over dx} =30 \times 2^4=30 \times 16=480\]
thank you very much
I was stuck
thinking about our answer to see if it makes sense, 480 is a big number , if that is our gradient at that point it is very steep but our equation for y is proportional to x^4 which gets large very quickly, so it makes sense that the slope is so steep

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