A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Assume that there are 8 different issues
of Popular Science, 7 different issues of Time,
and 4 different issues of Sports Illustrated, including
the December 1st issue, on the rack. You
choose 4 of them at random.
(1) What is the probability that you choose 3
issues of Popular Science and 1 issue of Time?
(2) What is the probability that you choose at
least 3 of the Time magazines?
anonymous
 4 years ago
Assume that there are 8 different issues of Popular Science, 7 different issues of Time, and 4 different issues of Sports Illustrated, including the December 1st issue, on the rack. You choose 4 of them at random. (1) What is the probability that you choose 3 issues of Popular Science and 1 issue of Time? (2) What is the probability that you choose at least 3 of the Time magazines?

This Question is Closed

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.0P(1) = 4C3 * (7/19)*(8/18)*(7/17)*(6/16)

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1P(3 PS and 1 Ti) = [C(8,3)C(7,1)] / C(19,4) = 98/969 = .101 approx

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1See if you wrote the problem correctly. I was expecting a restriction about the Dec 1 SI.

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Mr. Cow has 98/969 = .101 approx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it never specifies the 1 december 1st issue

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1On the first part, Mr. Cow and I agree. Check every word of the problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.098/969 is correct .101 is not

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1yes, are you to leave answers as fractions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i guess so it only worked with 969 but says .101 i tried it multiple times haha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the next one does specify

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.0for next part > .1174 or 455/3876

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.12) at least 3 T [C(7,3) C(8,1) + C(7,3)C(4,1) +C(7,4)] / C(19,4) = 455 / 3 876 = .117 approx

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1You are a genius guy. What's up with my fraction. I'll check.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you so much man you have helped save me
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.