anonymous
  • anonymous
Assume that there are 8 different issues of Popular Science, 7 different issues of Time, and 4 different issues of Sports Illustrated, including the December 1st issue, on the rack. You choose 4 of them at random. (1) What is the probability that you choose 3 issues of Popular Science and 1 issue of Time? (2) What is the probability that you choose at least 3 of the Time magazines?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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dumbcow
  • dumbcow
P(1) = 4C3 * (7/19)*(8/18)*(7/17)*(6/16)
Directrix
  • Directrix
P(3 PS and 1 Ti) = [C(8,3)C(7,1)] / C(19,4) = 98/969 = .101 approx
anonymous
  • anonymous
no

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anonymous
  • anonymous
that didnt work
Directrix
  • Directrix
See if you wrote the problem correctly. I was expecting a restriction about the Dec 1 SI.
Directrix
  • Directrix
Mr. Cow has 98/969 = .101 approx
anonymous
  • anonymous
it never specifies the 1 december 1st issue
Directrix
  • Directrix
On the first part, Mr. Cow and I agree. Check every word of the problem.
anonymous
  • anonymous
98/969 is correct .101 is not
anonymous
  • anonymous
same thing right
Directrix
  • Directrix
yes, are you to leave answers as fractions?
anonymous
  • anonymous
i guess so it only worked with 969 but says .101 i tried it multiple times haha
anonymous
  • anonymous
the next one does specify
dumbcow
  • dumbcow
for next part -> .1174 or 455/3876
anonymous
  • anonymous
Genius guys
Directrix
  • Directrix
2) at least 3 T [C(7,3) C(8,1) + C(7,3)C(4,1) +C(7,4)] / C(19,4) = 455 / 3 876 = .117 approx
Directrix
  • Directrix
You are a genius guy. What's up with my fraction. I'll check.
anonymous
  • anonymous
thank you so much man you have helped save me

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