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anonymous
 4 years ago
Assume that there are 8 different issues
of Popular Science, 7 different issues of Time,
and 4 different issues of Sports Illustrated, including
the December 1st issue, on the rack. You
choose 4 of them at random.
(1) What is the probability that you choose 3
issues of Popular Science and 1 issue of Time?
(2) What is the probability that you choose at
least 3 of the Time magazines?
anonymous
 4 years ago
Assume that there are 8 different issues of Popular Science, 7 different issues of Time, and 4 different issues of Sports Illustrated, including the December 1st issue, on the rack. You choose 4 of them at random. (1) What is the probability that you choose 3 issues of Popular Science and 1 issue of Time? (2) What is the probability that you choose at least 3 of the Time magazines?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0P(1) = 4C3 * (7/19)*(8/18)*(7/17)*(6/16)

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1P(3 PS and 1 Ti) = [C(8,3)C(7,1)] / C(19,4) = 98/969 = .101 approx

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1See if you wrote the problem correctly. I was expecting a restriction about the Dec 1 SI.

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Mr. Cow has 98/969 = .101 approx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it never specifies the 1 december 1st issue

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1On the first part, Mr. Cow and I agree. Check every word of the problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.098/969 is correct .101 is not

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1yes, are you to leave answers as fractions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i guess so it only worked with 969 but says .101 i tried it multiple times haha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the next one does specify

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for next part > .1174 or 455/3876

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.12) at least 3 T [C(7,3) C(8,1) + C(7,3)C(4,1) +C(7,4)] / C(19,4) = 455 / 3 876 = .117 approx

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1You are a genius guy. What's up with my fraction. I'll check.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you so much man you have helped save me
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