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anonymous

  • 4 years ago

Let f(x) = x^(4/3) - 7 x^(-8/3) f '(x) = A xB + C xD, where I think they want me to find a,b,c & d

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  1. anonymous
    • 4 years ago
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    I think I use the power rule

  2. TuringTest
    • 4 years ago
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    exactly, and what dd you get?

  3. anonymous
    • 4 years ago
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    f(x)= rx^r-1

  4. anonymous
    • 4 years ago
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    and I get ...

  5. anonymous
    • 4 years ago
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    4/3x^1/3- -56/3x^-3/2 is that right?

  6. TuringTest
    • 4 years ago
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    first term is right, but not the second what is\[-\frac83-1\]?

  7. anonymous
    • 4 years ago
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    -7/3

  8. TuringTest
    • 4 years ago
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    \[-\frac83-1=-\frac83-\frac33=-\frac{11}3\]which is your exponent on the second term

  9. anonymous
    • 4 years ago
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    so 4/3x^1/3- -56x^-11/3

  10. TuringTest
    • 4 years ago
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    negative times negative is positive we never write -- and you forgot to divide 56/3 in your final answer

  11. anonymous
    • 4 years ago
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    oh yeah thanks didnt see that

  12. anonymous
    • 4 years ago
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    wait something is wrong 56x^11/3

  13. anonymous
    • 4 years ago
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    i mean 56x^-11/3

  14. TuringTest
    • 4 years ago
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    (56/3)x^(-11/3)

  15. anonymous
    • 4 years ago
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    man I need to be careful

  16. TuringTest
    • 4 years ago
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    -7x^(-8/3) -7(-8/3)x^(-8/3-1) 56/3x^(-11/3) yeah, algebra can get you if you're not paying attention :P

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