anonymous
  • anonymous
Let f(x) = x^(4/3) - 7 x^(-8/3) f '(x) = A xB + C xD, where I think they want me to find a,b,c & d
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I think I use the power rule
TuringTest
  • TuringTest
exactly, and what dd you get?
anonymous
  • anonymous
f(x)= rx^r-1

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anonymous
  • anonymous
and I get ...
anonymous
  • anonymous
4/3x^1/3- -56/3x^-3/2 is that right?
TuringTest
  • TuringTest
first term is right, but not the second what is\[-\frac83-1\]?
anonymous
  • anonymous
-7/3
TuringTest
  • TuringTest
\[-\frac83-1=-\frac83-\frac33=-\frac{11}3\]which is your exponent on the second term
anonymous
  • anonymous
so 4/3x^1/3- -56x^-11/3
TuringTest
  • TuringTest
negative times negative is positive we never write -- and you forgot to divide 56/3 in your final answer
anonymous
  • anonymous
oh yeah thanks didnt see that
anonymous
  • anonymous
wait something is wrong 56x^11/3
anonymous
  • anonymous
i mean 56x^-11/3
TuringTest
  • TuringTest
(56/3)x^(-11/3)
anonymous
  • anonymous
man I need to be careful
TuringTest
  • TuringTest
-7x^(-8/3) -7(-8/3)x^(-8/3-1) 56/3x^(-11/3) yeah, algebra can get you if you're not paying attention :P

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