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anonymous
 4 years ago
Let f(x) = x^(4/3)  7 x^(8/3)
f '(x) = A xB + C xD, where
I think they want me to find a,b,c & d
anonymous
 4 years ago
Let f(x) = x^(4/3)  7 x^(8/3) f '(x) = A xB + C xD, where I think they want me to find a,b,c & d

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think I use the power rule

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1exactly, and what dd you get?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04/3x^1/3 56/3x^3/2 is that right?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1first term is right, but not the second what is\[\frac831\]?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac831=\frac83\frac33=\frac{11}3\]which is your exponent on the second term

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 4/3x^1/3 56x^11/3

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1negative times negative is positive we never write  and you forgot to divide 56/3 in your final answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh yeah thanks didnt see that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait something is wrong 56x^11/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0man I need to be careful

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.17x^(8/3) 7(8/3)x^(8/31) 56/3x^(11/3) yeah, algebra can get you if you're not paying attention :P
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