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anonymous
 4 years ago
Use the fact that the trigonometric functions are periodic to find the exact value of the expression.
sin405 degrees
tan405 degrees
csc 350
sin 9pi

4
anonymous
 4 years ago
Use the fact that the trigonometric functions are periodic to find the exact value of the expression. sin405 degrees tan405 degrees csc 350 sin 9pi  4

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dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.2sin(405) = sin(405360) = sin(45) = sqrt2/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I thought that the period for tan was 180

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.2csc(350) = csc(10) = csc(10) = 1/sin(10) = 5.759

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.2it is...so you go 2 periods but you still end up with reference angle of 45

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0please explain the csc

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.2350 is not quite 1 period 350 360 = 10 trig identity: csc(theta) = csc(theta)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do u get this: 1/sin(10) = 5.759

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.2the last one is identical to the first except its in radians > sin(9pi/4) = sqrt2/2

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.2oh i used a calculator...if you have to have an exact expression you have to use double and halfangle formulas

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0list all the trig identities please

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin 9pi  4 what about that problem?
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