Use the fact that the trigonometric functions are periodic to find the exact value of the expression. sin405 degrees tan405 degrees csc 350 sin 9pi ---- 4

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Use the fact that the trigonometric functions are periodic to find the exact value of the expression. sin405 degrees tan405 degrees csc 350 sin 9pi ---- 4

Mathematics
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sin(405) = sin(405-360) = sin(45) = sqrt2/2
tan(405) = tan(45) = 1
I thought that the period for tan was 180

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csc(350) = csc(-10) = -csc(10) = -1/sin(10) = -5.759
it is...so you go 2 periods but you still end up with reference angle of 45
okay gotcha!
please explain the csc
350 is not quite 1 period 350 -360 = -10 trig identity: csc(-theta) = -csc(theta)
how do u get this: 1/sin(10) = -5.759
the last one is identical to the first except its in radians --> sin(9pi/4) = sqrt2/2
oh i used a calculator...if you have to have an exact expression you have to use double and half-angle formulas
list all the trig identities please
sin 9pi ---- 4 what about that problem?

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