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anonymous

  • 4 years ago

Use the fact that the trigonometric functions are periodic to find the exact value of the expression. sin405 degrees tan405 degrees csc 350 sin 9pi ---- 4

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  1. dumbcow
    • 4 years ago
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    sin(405) = sin(405-360) = sin(45) = sqrt2/2

  2. dumbcow
    • 4 years ago
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    tan(405) = tan(45) = 1

  3. anonymous
    • 4 years ago
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    I thought that the period for tan was 180

  4. dumbcow
    • 4 years ago
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    csc(350) = csc(-10) = -csc(10) = -1/sin(10) = -5.759

  5. dumbcow
    • 4 years ago
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    it is...so you go 2 periods but you still end up with reference angle of 45

  6. anonymous
    • 4 years ago
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    okay gotcha!

  7. anonymous
    • 4 years ago
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    please explain the csc

  8. dumbcow
    • 4 years ago
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    350 is not quite 1 period 350 -360 = -10 trig identity: csc(-theta) = -csc(theta)

  9. anonymous
    • 4 years ago
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    how do u get this: 1/sin(10) = -5.759

  10. dumbcow
    • 4 years ago
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    the last one is identical to the first except its in radians --> sin(9pi/4) = sqrt2/2

  11. dumbcow
    • 4 years ago
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    oh i used a calculator...if you have to have an exact expression you have to use double and half-angle formulas

  12. anonymous
    • 4 years ago
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    list all the trig identities please

  13. anonymous
    • 4 years ago
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    sin 9pi ---- 4 what about that problem?

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