anonymous
  • anonymous
Can someone please help me out with this problem: An object is thrown vertically upward and has a speed of 24m/s when it reaches two thirds of its maximum height above the launch point. Determine its maximum height. Please show me how to do this. Thanks in advance.
Physics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
are u there?
TuringTest
  • TuringTest
the velocity at the top is 0 we can use that to set up a kinematic equation for the last third of the motion upwards\[v_f^2=v_i^2+2ad\]acceleration is g (down) the initial velocity is given, the final velocity is 0, and the height it moves is one-third the total height h/3\[0=v_i^2-\frac23gh\]solve for h
anonymous
  • anonymous
hey eash more help me in my question

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anonymous
  • anonymous
Thanks for your help. What happened to the 2, that would be in front of the g?
TuringTest
  • TuringTest
it's still there, but I put it over the three we get from h/3
anonymous
  • anonymous
ok, what happened to the 2 in 2/3 go?
TuringTest
  • TuringTest
|dw:1328243865207:dw|we are just considering the last third of its flight over the distance h/3 after that if we find h we know the total height
anonymous
  • anonymous
okay that helped a lot.
TuringTest
  • TuringTest
\[v_f^2=v_i^2+2ad\]\[d=\frac h3\]\[a=-g\]\[v_f=0\]so we get\[0=v_i^2-2g\cdot\frac h3=v_i^2-\frac23gh\]

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