anonymous
  • anonymous
Help with finding principal value. I've memorized the unit circle , but my teacher was very vague over principal values.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i dont get how \[\sin^{-1} (-\sqrt{2}/2) is -\pi/4\]
anonymous
  • anonymous
because \[\sin(-\frac{\pi}{4})=-\frac{\sqrt{2}}{2}\]
anonymous
  • anonymous
you are looking for the angle (number) in the interval \[[-\frac{\pi}{2},\frac{\pi}{2}]\] where the sine is your number

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anonymous
  • anonymous
there are an infinite number of numbers whose sine is anything between -1 and 1 because it is periodic, but only one in the above mentioned interval
anonymous
  • anonymous
So it sin inverse would only be in the first quadrant of the unit circle?
Mertsj
  • Mertsj
No. It could also be in the 4th quadrant. All values for sin^-1 are, by definition, in quadrants I or IV

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