anonymous
  • anonymous
A 512 Hz tuning fork is placed over a long tube that is submerged in a column of water. The speed of sound in the air during this experiment is 343 m/s. The tube is place at one position and resonance is heard. It is raised to a new position and resonance is heard. What is the distance between the two resonances?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
There are numerous distances. Essentially, any distance equal to the wavelength of any harmonic of the 512 Hz signal will create a resonance.
anonymous
  • anonymous
D:
anonymous
  • anonymous
I feel so stupid i figured it out...just realized the answer was in centimeters -_-. So if anyone wants to see my answer it's v=(wavelength)(frequency) and d = (1/2)(wavelength) \[343 m/s \div 512s\] = .66992 m = wavelength .66992m(1/2) = .3349m = distance convert that to cm it's 33.5 cm ugh physics

Looking for something else?

Not the answer you are looking for? Search for more explanations.