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anonymous
 4 years ago
how do I find the slope of the curve at x = 9. when Let f(x)=5 x^2 + 2/x^2. (this new to me)
anonymous
 4 years ago
how do I find the slope of the curve at x = 9. when Let f(x)=5 x^2 + 2/x^2. (this new to me)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I first find the f'(x) = 10x+1/2x right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or dy/dx= 10x4x^3 right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then I plug in for x=9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then it is 10(9)4(9)^3=

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh the exponent is neg, so you are dividing by 9^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait is ot 10(9)4(9)^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is correct > 90 +4/9^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you did something wrong when you wrote ...90 2916 property of neg exponents: x^n = 1/x^n right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.010(9)  4(9)^3 = 90 +4/9^3 = 90 +4/729 = 89.9945

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was multiplying 4(9)^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that the approximate or exact answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how can i find the exact number because they want me to find the exact anwser

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nevermind I found it thanx
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