anonymous
  • anonymous
how do I find the slope of the curve at x = -9. when Let f(x)=5 x^2 + 2/x^2. (this new to me)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I first find the f'(x) = 10x+1/-2x right ?
anonymous
  • anonymous
or dy/dx= 10x-4x^-3 right
anonymous
  • anonymous
then I plug in for x=-9

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dumbcow
  • dumbcow
yes correct
anonymous
  • anonymous
then it is 10(-9)-4(-9)^3=
anonymous
  • anonymous
-90-2916=
dumbcow
  • dumbcow
oh the exponent is neg, so you are dividing by 9^3
anonymous
  • anonymous
wait is ot 10(-9)-4(-9)^-3
dumbcow
  • dumbcow
that is correct --> -90 +4/9^3
dumbcow
  • dumbcow
(-9)^-3 = -1/9^3
anonymous
  • anonymous
wait im lost
anonymous
  • anonymous
so its -90-1/9^3
dumbcow
  • dumbcow
you did something wrong when you wrote ...-90 -2916 property of neg exponents: x^-n = 1/x^n right
anonymous
  • anonymous
yes
dumbcow
  • dumbcow
10(-9) - 4(-9)^-3 = -90 +4/9^3 = -90 +4/729 = -89.9945
anonymous
  • anonymous
oh ok divide 4/729
anonymous
  • anonymous
I was multiplying 4(9)^3
dumbcow
  • dumbcow
:)
anonymous
  • anonymous
is that the approximate or exact answer?
anonymous
  • anonymous
how can i find the exact number because they want me to find the exact anwser
anonymous
  • anonymous
nevermind I found it thanx

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