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anonymous
 4 years ago
FINAL ONE!!!! THANKS TO ALL THOSE EXPLAINING THESE PROBLEMS FOR ME!!!!!
Assume that you have a total of 14 people on the committee: 2 black males, 5 black females, 2 white males, and 5 white females.
Party rules require that at least one black and at
least one female hold one of the three offices.
In how many ways can the officers be chosen
while still conforming to party rules?
anonymous
 4 years ago
FINAL ONE!!!! THANKS TO ALL THOSE EXPLAINING THESE PROBLEMS FOR ME!!!!! Assume that you have a total of 14 people on the committee: 2 black males, 5 black females, 2 white males, and 5 white females. Party rules require that at least one black and at least one female hold one of the three offices. In how many ways can the officers be chosen while still conforming to party rules?

This Question is Closed

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1Give me some time, I'm trying to solve this. :)

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0I'm getting 250. I'm not entirely sure about this answer however. Can someone verify?

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0Gotten by the formula \[\left( \begin{matrix} 5 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 9 \\ 2 \end{matrix}\right) + \left( \begin{matrix} 2 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 5 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 7 \\ 1 \end{matrix}\right)\]However, I'm pretty sure there are committees I've counted at least twice.

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have a limited number of tries?

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0Next possibility I have is\[5\cdot \left( \begin{matrix} 11 \\ 2 \end{matrix}\right) + 2\cdot 10 \cdot 11 +10\]This was obtained by breaking down into three case. Case 1: 0 black males. Case 2: 1 black male. Case 3: 2 black males.

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0505 is what it results in

barrycarter
 4 years ago
Best ResponseYou've already chosen the best response.0Total number of committees ignoring rules: C(14,3) or 364 Committees with just males: C(4,3) or 4 Committees with just whites: C(7,3) or 35 Committees with just white males: 0 (there are only 2 white males). So the total is 364435 or 325.

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1Let's find the total no. of ways of alloting= 14 C3=364 now we'll subtract the following cases from total no. of ways commitee with whites= 7C3=35 commitee with males= 4C3=4 total =39 Our required =36439=325 ways

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i have to give up i am leaving 4 unanswered

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I cant see the screen

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.1Givng up is not an option. Are you talking about problem #4 or 4 unworked problems?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0they all are posted on here we have left two unanswered completely then some partials can you view them through my profile?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have thank you so much for everything
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