anonymous
  • anonymous
FINAL ONE!!!! THANKS TO ALL THOSE EXPLAINING THESE PROBLEMS FOR ME!!!!! Assume that you have a total of 14 people on the committee: 2 black males, 5 black females, 2 white males, and 5 white females. Party rules require that at least one black and at least one female hold one of the three offices. In how many ways can the officers be chosen while still conforming to party rules?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ash2326
  • ash2326
Give me some time, I'm trying to solve this. :)
KingGeorge
  • KingGeorge
I'm getting 250. I'm not entirely sure about this answer however. Can someone verify?
KingGeorge
  • KingGeorge
Gotten by the formula \[\left( \begin{matrix} 5 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 9 \\ 2 \end{matrix}\right) + \left( \begin{matrix} 2 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 5 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 7 \\ 1 \end{matrix}\right)\]However, I'm pretty sure there are committees I've counted at least twice.

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anonymous
  • anonymous
ill check
anonymous
  • anonymous
it says incorrect
KingGeorge
  • KingGeorge
Do you have a limited number of tries?
anonymous
  • anonymous
no
KingGeorge
  • KingGeorge
Next possibility I have is\[5\cdot \left( \begin{matrix} 11 \\ 2 \end{matrix}\right) + 2\cdot 10 \cdot 11 +10\]This was obtained by breaking down into three case. Case 1: 0 black males. Case 2: 1 black male. Case 3: 2 black males.
KingGeorge
  • KingGeorge
505 is what it results in
anonymous
  • anonymous
incorrect
barrycarter
  • barrycarter
Total number of committees ignoring rules: C(14,3) or 364 Committees with just males: C(4,3) or 4 Committees with just whites: C(7,3) or 35 Committees with just white males: 0 (there are only 2 white males). So the total is 364-4-35 or 325.
anonymous
  • anonymous
that did not work
ash2326
  • ash2326
Let's find the total no. of ways of alloting= 14 C3=364 now we'll subtract the following cases from total no. of ways commitee with whites= 7C3=35 commitee with males= 4C3=4 total =39 Our required =364-39=325 ways
anonymous
  • anonymous
well i have to give up i am leaving 4 unanswered
anonymous
  • anonymous
I cant see the screen
anonymous
  • anonymous
or the paer
Directrix
  • Directrix
Givng up is not an option. Are you talking about problem #4 or 4 unworked problems?
anonymous
  • anonymous
sorry just 3
anonymous
  • anonymous
3 problems
anonymous
  • anonymous
they all are posted on here we have left two unanswered completely then some partials can you view them through my profile?
anonymous
  • anonymous
I have thank you so much for everything
anonymous
  • anonymous
**Bookmark**

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