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anonymous

  • 4 years ago

FINAL ONE!!!! THANKS TO ALL THOSE EXPLAINING THESE PROBLEMS FOR ME!!!!! Assume that you have a total of 14 people on the committee: 2 black males, 5 black females, 2 white males, and 5 white females. Party rules require that at least one black and at least one female hold one of the three offices. In how many ways can the officers be chosen while still conforming to party rules?

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  1. ash2326
    • 4 years ago
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    Give me some time, I'm trying to solve this. :)

  2. KingGeorge
    • 4 years ago
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    I'm getting 250. I'm not entirely sure about this answer however. Can someone verify?

  3. KingGeorge
    • 4 years ago
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    Gotten by the formula \[\left( \begin{matrix} 5 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 9 \\ 2 \end{matrix}\right) + \left( \begin{matrix} 2 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 5 \\ 1 \end{matrix}\right) \cdot \left( \begin{matrix} 7 \\ 1 \end{matrix}\right)\]However, I'm pretty sure there are committees I've counted at least twice.

  4. anonymous
    • 4 years ago
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    ill check

  5. anonymous
    • 4 years ago
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    it says incorrect

  6. KingGeorge
    • 4 years ago
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    Do you have a limited number of tries?

  7. anonymous
    • 4 years ago
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    no

  8. KingGeorge
    • 4 years ago
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    Next possibility I have is\[5\cdot \left( \begin{matrix} 11 \\ 2 \end{matrix}\right) + 2\cdot 10 \cdot 11 +10\]This was obtained by breaking down into three case. Case 1: 0 black males. Case 2: 1 black male. Case 3: 2 black males.

  9. KingGeorge
    • 4 years ago
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    505 is what it results in

  10. anonymous
    • 4 years ago
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    incorrect

  11. barrycarter
    • 4 years ago
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    Total number of committees ignoring rules: C(14,3) or 364 Committees with just males: C(4,3) or 4 Committees with just whites: C(7,3) or 35 Committees with just white males: 0 (there are only 2 white males). So the total is 364-4-35 or 325.

  12. anonymous
    • 4 years ago
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    that did not work

  13. ash2326
    • 4 years ago
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    Let's find the total no. of ways of alloting= 14 C3=364 now we'll subtract the following cases from total no. of ways commitee with whites= 7C3=35 commitee with males= 4C3=4 total =39 Our required =364-39=325 ways

  14. anonymous
    • 4 years ago
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    well i have to give up i am leaving 4 unanswered

  15. anonymous
    • 4 years ago
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    I cant see the screen

  16. anonymous
    • 4 years ago
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    or the paer

  17. Directrix
    • 4 years ago
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    Givng up is not an option. Are you talking about problem #4 or 4 unworked problems?

  18. anonymous
    • 4 years ago
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    sorry just 3

  19. anonymous
    • 4 years ago
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    3 problems

  20. anonymous
    • 4 years ago
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    they all are posted on here we have left two unanswered completely then some partials can you view them through my profile?

  21. anonymous
    • 4 years ago
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    I have thank you so much for everything

  22. anonymous
    • 4 years ago
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    **Bookmark**

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