@ Mr. DumbCow
Will you take a look at these (similar to others you've done tonight)? Thanks.
Assume that you have 5 different types of
vegetables and 10 different types of fruit. A vegetable salad consists of a mixture of any 3 types of vegetables, and a fruit salad consists of a mixture of 2 kinds of fruit.
(1) In how many different ways can you prepare
a vegetable salad and a fruit salad?
(2) In how many different ways can you prepare
a vegetable salad or a fruit salad but not both?
(3) How many ways can you choose two different
kinds of salad?
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(1) 5C3 x 10C2
Parts 2 and 3? any idea?
i don't quite get what they mean for (2)
3) is same as part 1i think : 5C3 *10C2
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ill try it
Weirdly worded question.
I was thinking that in (2) the answer is the sum of 5C3 + 10C2
yeah ^^ just thought of that
they all are that way
the exam today wasnt so so bad but my goodness
55 is correct
Problems worthy of attack prove their worth by hitting back. (Piet Hein)
Anyone working on part 3?
is it not 450 ....5C3*10C2
(3) looks like 2! x 5C3 x 10C2... since 2 ways of selecting salad
#3 First, we need to determine the number of vegetable and fruit salads possible which is C(5,3) and C(10,2) receptively.
Then the product should give the right answer.
How do you get 395?
395 is wrong and so is 2!*C(5,3)*C(10,2)
do i add them instead of multiply
Is 450 correct?
@ Mr. Fool for Math
5C3*10C2 - [5C3 + 10C2]
haha we are running out of options
well there are 10 ways of choosing veg salad
45 ways of choosing fruit salad
maybe you can choose 2 veggie salads or 2 fruit salads as well
-> 450 + 10C2 + 45C2 = 1485
WE HAVE A WINNER!!!!!!!!!!!!!!!!!!
But when we "choose 2 veggie salads or 2 fruit salads as well" how come our choices are still different?
Direct thank you so much
This question is poorly worded when solvers have to "guess" what the question author means to say.
@ Mr. Fool for Math - I don't know but will work on it.
I agree with Directrix, this question is ill-worded.