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Directrix

  • 4 years ago

@ Mr. DumbCow Will you take a look at these (similar to others you've done tonight)? Thanks. cwhutche Assume that you have 5 different types of vegetables and 10 different types of fruit. A vegetable salad consists of a mixture of any 3 types of vegetables, and a fruit salad consists of a mixture of 2 kinds of fruit. (1) In how many different ways can you prepare a vegetable salad and a fruit salad? (2) In how many different ways can you prepare a vegetable salad or a fruit salad but not both? (3) How many ways can you choose two different kinds of salad?

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  1. campbell_st
    • 4 years ago
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    (1) 5C3 x 10C2

  2. Directrix
    • 4 years ago
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    Parts 2 and 3? any idea?

  3. dumbcow
    • 4 years ago
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    i don't quite get what they mean for (2) 3) is same as part 1i think : 5C3 *10C2

  4. anonymous
    • 4 years ago
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    ill try it

  5. anonymous
    • 4 years ago
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    it wasnt

  6. Directrix
    • 4 years ago
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    Weirdly worded question.

  7. campbell_st
    • 4 years ago
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    I was thinking that in (2) the answer is the sum of 5C3 + 10C2

  8. dumbcow
    • 4 years ago
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    yeah ^^ just thought of that

  9. anonymous
    • 4 years ago
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    they all are that way the exam today wasnt so so bad but my goodness

  10. anonymous
    • 4 years ago
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    55 is correct

  11. Directrix
    • 4 years ago
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    Problems worthy of attack prove their worth by hitting back. (Piet Hein)

  12. Directrix
    • 4 years ago
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    Anyone working on part 3?

  13. dumbcow
    • 4 years ago
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    is it not 450 ....5C3*10C2

  14. campbell_st
    • 4 years ago
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    (3) looks like 2! x 5C3 x 10C2... since 2 ways of selecting salad

  15. anonymous
    • 4 years ago
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    no

  16. anonymous
    • 4 years ago
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    #3 First, we need to determine the number of vegetable and fruit salads possible which is C(5,3) and C(10,2) receptively. Then the product should give the right answer.

  17. Directrix
    • 4 years ago
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    395 ?

  18. anonymous
    • 4 years ago
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    How do you get 395?

  19. anonymous
    • 4 years ago
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    395 is wrong and so is 2!*C(5,3)*C(10,2)

  20. anonymous
    • 4 years ago
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    do i add them instead of multiply

  21. anonymous
    • 4 years ago
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    Is 450 correct?

  22. anonymous
    • 4 years ago
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    no

  23. Directrix
    • 4 years ago
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    @ Mr. Fool for Math 5C3*10C2 - [5C3 + 10C2]

  24. dumbcow
    • 4 years ago
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    haha we are running out of options well there are 10 ways of choosing veg salad 45 ways of choosing fruit salad maybe you can choose 2 veggie salads or 2 fruit salads as well -> 450 + 10C2 + 45C2 = 1485 ??

  25. anonymous
    • 4 years ago
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    WE HAVE A WINNER!!!!!!!!!!!!!!!!!!

  26. anonymous
    • 4 years ago
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    1485

  27. anonymous
    • 4 years ago
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    But when we "choose 2 veggie salads or 2 fruit salads as well" how come our choices are still different?

  28. anonymous
    • 4 years ago
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    Direct thank you so much

  29. Directrix
    • 4 years ago
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    This question is poorly worded when solvers have to "guess" what the question author means to say. @ Mr. Fool for Math - I don't know but will work on it.

  30. anonymous
    • 4 years ago
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    I agree with Directrix, this question is ill-worded.

  31. anonymous
    • 4 years ago
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    I agree they just create confusion

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