anonymous
  • anonymous
find an expression for the nth partial sum Sn of the series summation of n=2 to infinity of 2[1/(2^n) -1/(2^(n+1)]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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campbell_st
  • campbell_st
get a common denominator \[2[(2^(n+1) - 2^n)/(2^n)(2^(n+1)]\] rewrite as \[2[2^n(2 -1)/2^n(2^(n+1)]\] cancel the common factor 2^n gives \[2/2^(n+1) = 2/(2\times2^n)\] cancel another common factor 2 gives 1/2^n
barrycarter
  • barrycarter
Other hint: this is a telescoping series.

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