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anonymous
 4 years ago
Make a ttable of values for y = x2 + 4x + 1. A suggestion is to begin your values with 5.
1.List your ordered pairs from the table. Use parenthesis for each pair, such as (1,2).
2.Which point is the vertex of the parabola?
a) (2, 3)
b) (2, 3)
c) (2, 3)
d) (2, 3)
3. The line which you folded is called the line of symmetry. This divides the parabola into two matching halves or mirror images. The equation of the line is x = ___ because it is vertical. Look to see where your folded line crosses the xaxis. Choose the equation below.
a) x = 2
b) x = 2
c) x = 0
d)None
anonymous
 4 years ago
Make a ttable of values for y = x2 + 4x + 1. A suggestion is to begin your values with 5. 1.List your ordered pairs from the table. Use parenthesis for each pair, such as (1,2). 2.Which point is the vertex of the parabola? a) (2, 3) b) (2, 3) c) (2, 3) d) (2, 3) 3. The line which you folded is called the line of symmetry. This divides the parabola into two matching halves or mirror images. The equation of the line is x = ___ because it is vertical. Look to see where your folded line crosses the xaxis. Choose the equation below. a) x = 2 b) x = 2 c) x = 0 d)None

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You can write a table on your own. On to the vertex; When an equation is written as: \[f(x)=ax^2+bx+c\] The vertex of a parabola will be the point: \[(\frac{b}{2a},f(\frac{b}{2a}))\] \[Vertex (\frac{4}{2(1)},f(\frac{4}{2(1)}))=(2, f(2))=(2,3)\] To find the line of symmetry, you can rewrite the equation to this form and the line of symmetry will be at x=h: \[f(x)=a(xh)^2+K\] To do this, you need to complete the square for x. \[ y = x^2 + 4x + 1\] \[y=1(x^2+4x+44+1)=(x+2)^23\] From this we can see that h=2. The line of symmetry is at x=h=2.
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