anonymous
  • anonymous
Show that p ^ ~p is a contradiction.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
It's true!
anonymous
  • anonymous
p xor not p is always true
anonymous
  • anonymous
oh..... you meant p and not p...... that's false

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JamesJ
  • JamesJ
if p = true, i.e., T, then p ^ ~p = T ^ ~T = T ^ F = F Similarly if p = F.
anonymous
  • anonymous
from the statement of p and not p, it is clear that either p or not p has to be false, so the result is naturally false.
anonymous
  • anonymous
Ok thanks guys. I see the correlation now.

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