A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

can any one give me interpretation of delta function potential

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    To be correct, the delta "function" is a (irregular) distribution (not a function), so from the physical point of view it only makes sense to talk about it when integrating over it. You can imagine it as a the limit of a Gaussian, where the width approaches zero while the integral stays constant. (Hence the height gets infinity.) If it's (delta(x-x')) together with any other function f(x) inside of an integral, the integral just leads to the value of the function at the point x=x', i.e. f(x'). Don't know if this really helps, but in principle I would say it's more like a mathematical trick (or property) then a physical interpretation of it.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.