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AravindG
 4 years ago
a small cylinder of radius r is released coaxially from point A inside the fixed large cylindrical bowl of radius r as in fug.if the friction between the small and large cylinder is sufficient enough t o prevent any slipping then find (a) the fractions of total KE vs rotational when the cylinder reaches the bottom .(b) the normal force exerted by small cylinder on the larger one when it is at bottom.
AravindG
 4 years ago
a small cylinder of radius r is released coaxially from point A inside the fixed large cylindrical bowl of radius r as in fug.if the friction between the small and large cylinder is sufficient enough t o prevent any slipping then find (a) the fractions of total KE vs rotational when the cylinder reaches the bottom .(b) the normal force exerted by small cylinder on the larger one when it is at bottom.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you use conservation law of E? between A& bottom point

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in point A it has PE & in bottom has KE (rotational & transitional KE) do you get my goal?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[mgr=(1/2mv ^{2})+(1/2)I \omega ^{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for sylender \[I=(1/2mr ^{2})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0from 2nd law of newton have \[Nmg=mv ^{2}/R\] right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in part 1 question ask this: \[(0.5mv ^{2}+0.5\omega ^{2})/(0.5I \omega ^{2})\] so v=Rw i think ithink answer is:2[(R/r)]^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry one of the i think is lampoon

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0big cylender is frictionless ok?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i answered part b on top
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