anonymous
  • anonymous
What is this rounded to the nearest tenth?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt{46}\]
anonymous
  • anonymous
Show work please.. I need a better understanding
anonymous
  • anonymous
A. 6.6 B. 6.7 C. 6.8 D. 6.9

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phi
  • phi
are you allowed a calculator? if so, find sqrt(46) and write down the answer, including 2 numbers after the decimal point. then round that number.
anonymous
  • anonymous
I can't I have a basic calculator :(
anonymous
  • anonymous
online calculator
phi
  • phi
type sqrt(46)= in the google search window |dw:1328287654901:dw|
anonymous
  • anonymous
oh ya forgot about Google you can define and solve math in it.
anonymous
  • anonymous
so does that make it B
anonymous
  • anonymous
Phi?
phi
  • phi
the sqrt(46) is about 6.78 but to round it the the nearest tenth you have to choose 6.7 or 6.8 look at a number line |dw:1328287934700:dw|
phi
  • phi
or just follow the rule. look at the number after the 7. If it is 5 or bigger, make the 7 and 8
anonymous
  • anonymous
I think it's 6.8. I'm pretty sure... Am I right?
phi
  • phi
yes. if you started with 6.74, you would round it to 6.7 (because the 4 after the 7 is less than 5)
phi
  • phi
but you have 6.78, and 8 is 5 or bigger, so round to 6.8

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