## Lukecrayonz 4 years ago Vectors (Precalculus)

1. Lukecrayonz

a) (4,3) b) (-2,1) c) (-7,1)

3. Lukecrayonz

Explain C please:) and I have a new one for you.

4. Lukecrayonz

2*u you get if you multiply its coordinates by 2, 2*v also and than just substract them: first coordinate of u minus first coordinate of v and second minus second and you'll get that result

v=($5/\sqrt{2},5/\sqrt{2}$)

7. Lukecrayonz

How did you get that?;o

8. Lukecrayonz

Nevermind i got it.

:D

10. Lukecrayonz

No wait D:I didnt.

11. Lukecrayonz

Actually forget it. I don't even need to do these problems, I've been doing the wrong ones!

12. Lukecrayonz

I was wondering why I never learned any of this!

13. Lukecrayonz

http://screensnapr.com/v/Hws0vK.png C of this part :D

first you find the unit vector (vector which length is 1) in the direction of the given vector by formula $u _{0}=u/\left| u \right|=(3,3)/\sqrt{(3^2+3^2)}=(1/\sqrt{2},1/\sqrt{2})$ ...than your vector is $v=5\times(1/\sqrt{2},1/\sqrt{2})=(5/\sqrt{2},5/\sqrt{2})$