Lukecrayonz
  • Lukecrayonz
Vectors (Precalculus)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Lukecrayonz
  • Lukecrayonz
http://screensnapr.com/v/FfJoiS.png
nenadmatematika
  • nenadmatematika
a) (4,3) b) (-2,1) c) (-7,1)
Lukecrayonz
  • Lukecrayonz
Explain C please:) and I have a new one for you.

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Lukecrayonz
  • Lukecrayonz
http://screensnapr.com/v/rx9TyR.png Just #29
nenadmatematika
  • nenadmatematika
2*u you get if you multiply its coordinates by 2, 2*v also and than just substract them: first coordinate of u minus first coordinate of v and second minus second and you'll get that result
nenadmatematika
  • nenadmatematika
v=(\[5/\sqrt{2},5/\sqrt{2}\])
Lukecrayonz
  • Lukecrayonz
How did you get that?;o
Lukecrayonz
  • Lukecrayonz
Nevermind i got it.
nenadmatematika
  • nenadmatematika
:D
Lukecrayonz
  • Lukecrayonz
No wait D:I didnt.
Lukecrayonz
  • Lukecrayonz
Actually forget it. I don't even need to do these problems, I've been doing the wrong ones!
Lukecrayonz
  • Lukecrayonz
I was wondering why I never learned any of this!
Lukecrayonz
  • Lukecrayonz
http://screensnapr.com/v/Hws0vK.png C of this part :D
nenadmatematika
  • nenadmatematika
first you find the unit vector (vector which length is 1) in the direction of the given vector by formula \[u _{0}=u/\left| u \right|=(3,3)/\sqrt{(3^2+3^2)}=(1/\sqrt{2},1/\sqrt{2})\] ...than your vector is \[v=5\times(1/\sqrt{2},1/\sqrt{2})=(5/\sqrt{2},5/\sqrt{2})\]
nenadmatematika
  • nenadmatematika
I must go now, I'll answer you later, good luck :D

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