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anonymous

  • 4 years ago

e^2x -7e^2x+12=0 there are 2 answers they want both

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  1. barrycarter
    • 4 years ago
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    Replacing e^(2x) with y, we have: y - 7*y + 12 = 0 or y=2 Thus e^(2x) = 2 We can rewrite e^(2x) as (e^x)^2, so we know that: e^x = +- Sqrt[2] = +-Sqrt[2^(1/2)] Taking the log, the answers are: x = Log[2]/2 and x= Log[2]/2 + I*Pi (the second answer is complex)

  2. anonymous
    • 4 years ago
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    webwork says that isnt the right answer

  3. barrycarter
    • 4 years ago
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    wolframalpha.com seems to agree with me: http://fwd4.me/0m5L

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