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anonymous
 4 years ago
e^2x 7e^2x+12=0
there are 2 answers they want both
anonymous
 4 years ago
e^2x 7e^2x+12=0 there are 2 answers they want both

This Question is Closed

barrycarter
 4 years ago
Best ResponseYou've already chosen the best response.0Replacing e^(2x) with y, we have: y  7*y + 12 = 0 or y=2 Thus e^(2x) = 2 We can rewrite e^(2x) as (e^x)^2, so we know that: e^x = + Sqrt[2] = +Sqrt[2^(1/2)] Taking the log, the answers are: x = Log[2]/2 and x= Log[2]/2 + I*Pi (the second answer is complex)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0webwork says that isnt the right answer

barrycarter
 4 years ago
Best ResponseYou've already chosen the best response.0wolframalpha.com seems to agree with me: http://fwd4.me/0m5L
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