anonymous
  • anonymous
Can anyone help me prove proerties of vectors?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
prove that u+v is a vector in R^n
cristiann
  • cristiann
u=(u1,...,un), v=(v1,...vn)=>u+v=(u1+v1,...un+vn) since each vector has real coordinates and the sum of two real numbers is a real number (closure property) it follows u+v in Rn
anonymous
  • anonymous
Hey that was awesome. LOL stick around I have 10 properties to prove and I suck at proving

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anonymous
  • anonymous
umm I have another one lol
anonymous
  • anonymous
u+v=v+u and we r disussing vectors in r^n
cristiann
  • cristiann
True, because of the commutativity property of real numbers (following the previous line of reasoning)
anonymous
  • anonymous
ya but i have to prove it and like how wld i do that
cristiann
  • cristiann
u=(u1,...,un), v=(v1,...vn)=>u+v=(u1+v1,...un+vn) v+u=(v1+u1,...vn+un) for each k, uk+vk=vk+uk (in real numbers) because of commutativity So u+v=v+u
anonymous
  • anonymous
Thanks :D
cristiann
  • cristiann
welcome :)
anonymous
  • anonymous
I need help with another one but maaybe i will do it another post so i can give u more medals :D
cristiann
  • cristiann
Not that interested in medals ... :) but you should try them for yourself... I should show you how to fish, not to fish in your place ...:)
anonymous
  • anonymous
heehe
anonymous
  • anonymous
lol i am figuring this one out on my own :D
cristiann
  • cristiann
:) maybe you should put the question in the form "is this correct?"
anonymous
  • anonymous
hehe ya i will do that for the next one :D
anonymous
  • anonymous
I did like 4 on my own :D lol
anonymous
  • anonymous
but now I am stuck Prove that cu is a vector in R^n
cristiann
  • cristiann
u=(u1,...,un), c in R, then cu=(cu1,...,cun), vector because the multiplication of two real numbers is a real number

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