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anonymous
 4 years ago
Can anyone help me prove proerties of vectors?
anonymous
 4 years ago
Can anyone help me prove proerties of vectors?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0prove that u+v is a vector in R^n

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.1u=(u1,...,un), v=(v1,...vn)=>u+v=(u1+v1,...un+vn) since each vector has real coordinates and the sum of two real numbers is a real number (closure property) it follows u+v in Rn

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hey that was awesome. LOL stick around I have 10 properties to prove and I suck at proving

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0umm I have another one lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u+v=v+u and we r disussing vectors in r^n

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.1True, because of the commutativity property of real numbers (following the previous line of reasoning)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya but i have to prove it and like how wld i do that

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.1u=(u1,...,un), v=(v1,...vn)=>u+v=(u1+v1,...un+vn) v+u=(v1+u1,...vn+un) for each k, uk+vk=vk+uk (in real numbers) because of commutativity So u+v=v+u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I need help with another one but maaybe i will do it another post so i can give u more medals :D

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.1Not that interested in medals ... :) but you should try them for yourself... I should show you how to fish, not to fish in your place ...:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i am figuring this one out on my own :D

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.1:) maybe you should put the question in the form "is this correct?"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hehe ya i will do that for the next one :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I did like 4 on my own :D lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but now I am stuck Prove that cu is a vector in R^n

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.1u=(u1,...,un), c in R, then cu=(cu1,...,cun), vector because the multiplication of two real numbers is a real number
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