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anonymous

  • 4 years ago

Simplify completely: the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the third power times y to the 2nd power all over 5 times x to the third power times y a.2x^9y64 + 4x^6y^3 b.2x^3y^2 + 4xy c.2x^3y^2 + 4y^2 d.2x^3y^2 + 4y

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  1. jhonyy9
    • 4 years ago
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    10x^6y^3 +20x^3y^2 --------------------- = 2x^3y^2 +4y 5x^3y so d. is right

  2. campbell_st
    • 4 years ago
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    \[(10x^6y^3 + 20x^3y^2)5x^3y\] common in the numerator is \[10x^3y^2\] so \[(10x^3y^2(x^3 + 2))/5x^3y\] cancel common factors... \[2y(x^3 + 2) = 2x^3y + 4y\]

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