PART1 Simplify completely: the quantity 5 times x to the third power plus 10 times x to the 2nd power plus 15 times x all over 5 times x a.x^2 + 10x^2 + 15x b.2x + 6 c.x^2 + 2x + 3 d.x^4 + 2x^3 + 3x^2 PART2 Simplify completely: the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x a.the quantity 3 times x to the third power plus 5 times x plus 2 all over x b.3x^3 + 5x + 2 c.3x^2 + 5x^2 + 2x d.3x^5 + 5x^3 + 2x^2

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PART1 Simplify completely: the quantity 5 times x to the third power plus 10 times x to the 2nd power plus 15 times x all over 5 times x a.x^2 + 10x^2 + 15x b.2x + 6 c.x^2 + 2x + 3 d.x^4 + 2x^3 + 3x^2 PART2 Simplify completely: the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x a.the quantity 3 times x to the third power plus 5 times x plus 2 all over x b.3x^3 + 5x + 2 c.3x^2 + 5x^2 + 2x d.3x^5 + 5x^3 + 2x^2

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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P1: (5x^3+10x^2+15x)/5x =x^2+5x+3
2x**
the rule is: when dividing, subtract the powers of the same pronumeral a^n/a^m = a^(n-m) use the rule to learn what to do

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Other answers:

so P1: C
mattt9 the second resulted term is 2x
i corrected that already. sorry.
did anyone figure out part 2?

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