anonymous
  • anonymous
Prove that in the elastic collision of two objects of identical mass, with one being a target initially at rest, the angle between their final velocity vectors is always 90 degrees.
Physics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

anonymous
  • anonymous
Prove that in the elastic collision of two objects of identical mass, with one being a target initially at rest, the angle between their final velocity vectors is always 90 degrees.
Physics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

JamesJ
  • JamesJ
Step 1: draw a diagram. I'd imagine the body initially at rest at the origin; the moving body approaching it along the negative x-axis. After the collision, by Conservation of Momentum, the x-components of the two bodies momentum must sum to the original momentum; and the y-components must sum to zero.
anonymous
  • anonymous
I think more important here is the conservation of energy, since the conservation of momentum solely cannot really constrain the angle between the final vectors.
JamesJ
  • JamesJ
Yes, you'll need both. I was just giving a starting point.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Actually, to proof the 90°, I think you need only the conservation of energy.
JamesJ
  • JamesJ
I'll be impressed if you can write down an argument with only the conservation of energy.
anonymous
  • anonymous
I did this and I don't know what to do after. attached a file
1 Attachment
anonymous
  • anonymous
What about \[ \frac{1}{2} m \vec v_1^2 = \frac{1}{2} m \vec v'_1^2 + \frac{1}{2} m \vec v'_2^2 \] \[\Rightarrow \vec v_1^2 = \vec v'_1^2 + \vec v'_2^2 \] Now think about the vectorial sum and the Pythagorean theorem and it's clear that this holds only if \[ \vec v'_1 \perp \vec v'_2\]
anonymous
  • anonymous
Okay, I see, you were right. Implicitly I was already using the momentum conservation. Sorry.
JamesJ
  • JamesJ
I was secretly hoping you were right. It's always good to be surprised. But in this case, I think we really do need both.
anonymous
  • anonymous
I don't even need to use any of the trig stuff to prove? So your equation is basically saying that the lines are in a pythygorean relation. The resultant is the initial momentum. |dw:1328308175582:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.