What is the acceleration at time t=3 of a particle whose position at time t is given by s(t)=3sqrt(x+1)^(1/3)
Note: The square root is the third root and it is being multiplied by another 3 that's the 3 in front.. so, it's 3 * third root(x+1)

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instead of x, it is t?

\[s(3)=3(\sqrt[3]{x+1})^{1/3}=3\sqrt[9]{4}\]

\[s(t)= 3(t+1)^{\frac{1}{3}}\]

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