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anonymous

  • 4 years ago

problem # 10. g(x)=log(x+5) when g(x)=5 help please

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  1. amistre64
    • 4 years ago
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    g(x) = log(x+5) g(x) = 5 ; therefore 5 = log(x+5)

  2. cwrw238
    • 4 years ago
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    oopps!!

  3. cwrw238
    • 4 years ago
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    amis is right

  4. amistre64
    • 4 years ago
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    now if log means base 10 10^5 = x+5 10^5 - 5 = x

  5. anonymous
    • 4 years ago
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    so the answer would be x=99995. thx!

  6. anonymous
    • 4 years ago
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    for the same problem but g(x-3) so i started by (x-3)=log (x+5)?? is that correct how iam doing it? the professor has two answers g(x+3)=log(x+2)i dont know how he got it.

  7. amistre64
    • 4 years ago
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    g(x+3) is different in that it defines "x" to be a certain .... value? x = "x+3" sooo g(x+3) = log((x+3)+5) g(x+3) = log(x+8)

  8. amistre64
    • 4 years ago
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    it helps if I read it right to begin with

  9. amistre64
    • 4 years ago
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    g(x-3) is the same concept tho g(x-3) = log((x-3)+5) g(x-3) = log(x-3+5) g(x-3) = log(x+2)

  10. amistre64
    • 4 years ago
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    in the first bit of your post; it says g(x) = yadayada in the second bit it says x = yadayada such that: g(x) = log(x+5) g(x-3) = log((x-3)+5)

  11. anonymous
    • 4 years ago
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    so what are you doing is g(x-3)=log (x+5).(x-3) is that what it is? iam a little confused, sorry.

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