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f(x)= -√x=1 Graph the functions and describe the domain and range of each function. anybody?

Mathematics
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your function has two equal signs in it.
f(x)= -√x+1
domain x >=-1 range y <= 0

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Other answers:

If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is \[[0,\infty)\]
^not true, x can be negative
Yes, but it will not yield a real number
I'm assuming he wants real numbers
x + 1 cannot be less than zero
Umm, how about I just post the thing that has all these on them
It says \[-\sqrt{x}=1\]
How can x be negative?
sqrt(x+1) not sqrt(x)
Oh i was going by the original post. Didn't see the updated one.
\[f(x)=-\sqrt{x+1} \,\,\text {or} f(x)=-\sqrt{x}+1?\]
That's what I thought cinar
that was a typo. sorry you guys!
So, which is it?
Use parentheses
f(x)= -√x+1
so 1 is not under the square root?
it is. x+1 are under the square root
OK, use parentheses next time \[\sqrt{x+1}>0, x>=-1\] Domain is \[[-1,\infty)\]
then domain is [-1,infinite) range is [0, infinite)
thank you!

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