anonymous
  • anonymous
f(x)= -√x=1 Graph the functions and describe the domain and range of each function. anybody?
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Hero
  • Hero
your function has two equal signs in it.
anonymous
  • anonymous
f(x)= -√x+1
Hero
  • Hero
domain x >=-1 range y <= 0

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is \[[0,\infty)\]
Hero
  • Hero
^not true, x can be negative
anonymous
  • anonymous
Yes, but it will not yield a real number
anonymous
  • anonymous
I'm assuming he wants real numbers
Hero
  • Hero
x + 1 cannot be less than zero
anonymous
  • anonymous
Umm, how about I just post the thing that has all these on them
anonymous
  • anonymous
It says \[-\sqrt{x}=1\]
anonymous
  • anonymous
How can x be negative?
Hero
  • Hero
sqrt(x+1) not sqrt(x)
anonymous
  • anonymous
Oh i was going by the original post. Didn't see the updated one.
anonymous
  • anonymous
\[f(x)=-\sqrt{x+1} \,\,\text {or} f(x)=-\sqrt{x}+1?\]
anonymous
  • anonymous
That's what I thought cinar
anonymous
  • anonymous
that was a typo. sorry you guys!
anonymous
  • anonymous
So, which is it?
Hero
  • Hero
Use parentheses
anonymous
  • anonymous
f(x)= -√x+1
anonymous
  • anonymous
so 1 is not under the square root?
anonymous
  • anonymous
it is. x+1 are under the square root
anonymous
  • anonymous
OK, use parentheses next time \[\sqrt{x+1}>0, x>=-1\] Domain is \[[-1,\infty)\]
anonymous
  • anonymous
then domain is [-1,infinite) range is [0, infinite)
anonymous
  • anonymous
thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.