## hugsandkisses 3 years ago f(x)= -√x=1 Graph the functions and describe the domain and range of each function. anybody?

1. Hero

your function has two equal signs in it.

2. hugsandkisses

f(x)= -√x+1

3. Hero

domain x >=-1 range y <= 0

4. rickjbr

If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is $[0,\infty)$

5. Hero

^not true, x can be negative

6. rickjbr

Yes, but it will not yield a real number

7. rickjbr

I'm assuming he wants real numbers

8. Hero

x + 1 cannot be less than zero

9. hugsandkisses

Umm, how about I just post the thing that has all these on them

10. rickjbr

It says $-\sqrt{x}=1$

11. rickjbr

How can x be negative?

12. Hero

sqrt(x+1) not sqrt(x)

13. rickjbr

Oh i was going by the original post. Didn't see the updated one.

14. cinar

$f(x)=-\sqrt{x+1} \,\,\text {or} f(x)=-\sqrt{x}+1?$

15. rickjbr

That's what I thought cinar

16. hugsandkisses

that was a typo. sorry you guys!

17. rickjbr

So, which is it?

18. Hero

Use parentheses

19. hugsandkisses

f(x)= -√x+1

20. rickjbr

so 1 is not under the square root?

21. hugsandkisses

it is. x+1 are under the square root

22. rickjbr

OK, use parentheses next time $\sqrt{x+1}>0, x>=-1$ Domain is $[-1,\infty)$

23. cinar

then domain is [-1,infinite) range is [0, infinite)

24. hugsandkisses

thank you!