anonymous
  • anonymous
f(x)= -√x=1 Graph the functions and describe the domain and range of each function. anybody?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Hero
  • Hero
your function has two equal signs in it.
anonymous
  • anonymous
f(x)= -√x+1
Hero
  • Hero
domain x >=-1 range y <= 0

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anonymous
  • anonymous
If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is \[[0,\infty)\]
Hero
  • Hero
^not true, x can be negative
anonymous
  • anonymous
Yes, but it will not yield a real number
anonymous
  • anonymous
I'm assuming he wants real numbers
Hero
  • Hero
x + 1 cannot be less than zero
anonymous
  • anonymous
Umm, how about I just post the thing that has all these on them
anonymous
  • anonymous
It says \[-\sqrt{x}=1\]
anonymous
  • anonymous
How can x be negative?
Hero
  • Hero
sqrt(x+1) not sqrt(x)
anonymous
  • anonymous
Oh i was going by the original post. Didn't see the updated one.
anonymous
  • anonymous
\[f(x)=-\sqrt{x+1} \,\,\text {or} f(x)=-\sqrt{x}+1?\]
anonymous
  • anonymous
That's what I thought cinar
anonymous
  • anonymous
that was a typo. sorry you guys!
anonymous
  • anonymous
So, which is it?
Hero
  • Hero
Use parentheses
anonymous
  • anonymous
f(x)= -√x+1
anonymous
  • anonymous
so 1 is not under the square root?
anonymous
  • anonymous
it is. x+1 are under the square root
anonymous
  • anonymous
OK, use parentheses next time \[\sqrt{x+1}>0, x>=-1\] Domain is \[[-1,\infty)\]
anonymous
  • anonymous
then domain is [-1,infinite) range is [0, infinite)
anonymous
  • anonymous
thank you!

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