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anonymous
 4 years ago
f(x)= √x=1
Graph the functions and describe the domain and range of each function. anybody?
anonymous
 4 years ago
f(x)= √x=1 Graph the functions and describe the domain and range of each function. anybody?

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.0your function has two equal signs in it.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0domain x >=1 range y <= 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is \[[0,\infty)\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0^not true, x can be negative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, but it will not yield a real number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm assuming he wants real numbers

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0x + 1 cannot be less than zero

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Umm, how about I just post the thing that has all these on them

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It says \[\sqrt{x}=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How can x be negative?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh i was going by the original post. Didn't see the updated one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=\sqrt{x+1} \,\,\text {or} f(x)=\sqrt{x}+1?\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's what I thought cinar

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that was a typo. sorry you guys!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 1 is not under the square root?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is. x+1 are under the square root

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK, use parentheses next time \[\sqrt{x+1}>0, x>=1\] Domain is \[[1,\infty)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then domain is [1,infinite) range is [0, infinite)
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