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hugsandkisses

f(x)= -√x=1 Graph the functions and describe the domain and range of each function. anybody?

  • 2 years ago
  • 2 years ago

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  1. Hero
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    your function has two equal signs in it.

    • 2 years ago
  2. hugsandkisses
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    f(x)= -√x+1

    • 2 years ago
  3. Hero
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    domain x >=-1 range y <= 0

    • 2 years ago
  4. rickjbr
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    If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is \[[0,\infty)\]

    • 2 years ago
  5. Hero
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    ^not true, x can be negative

    • 2 years ago
  6. rickjbr
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    Yes, but it will not yield a real number

    • 2 years ago
  7. rickjbr
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    I'm assuming he wants real numbers

    • 2 years ago
  8. Hero
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    x + 1 cannot be less than zero

    • 2 years ago
  9. hugsandkisses
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    Umm, how about I just post the thing that has all these on them

    • 2 years ago
  10. rickjbr
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    It says \[-\sqrt{x}=1\]

    • 2 years ago
  11. rickjbr
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    How can x be negative?

    • 2 years ago
  12. Hero
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    sqrt(x+1) not sqrt(x)

    • 2 years ago
  13. rickjbr
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    Oh i was going by the original post. Didn't see the updated one.

    • 2 years ago
  14. cinar
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    \[f(x)=-\sqrt{x+1} \,\,\text {or} f(x)=-\sqrt{x}+1?\]

    • 2 years ago
  15. rickjbr
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    That's what I thought cinar

    • 2 years ago
  16. hugsandkisses
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    that was a typo. sorry you guys!

    • 2 years ago
  17. rickjbr
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    So, which is it?

    • 2 years ago
  18. Hero
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    Use parentheses

    • 2 years ago
  19. hugsandkisses
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    f(x)= -√x+1

    • 2 years ago
  20. rickjbr
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    so 1 is not under the square root?

    • 2 years ago
  21. hugsandkisses
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    it is. x+1 are under the square root

    • 2 years ago
  22. rickjbr
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    OK, use parentheses next time \[\sqrt{x+1}>0, x>=-1\] Domain is \[[-1,\infty)\]

    • 2 years ago
  23. cinar
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    then domain is [-1,infinite) range is [0, infinite)

    • 2 years ago
  24. hugsandkisses
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    thank you!

    • 2 years ago
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