hugsandkisses
f(x)= -√x=1
Graph the functions and describe the domain and range of each function. anybody?
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Hero
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your function has two equal signs in it.
hugsandkisses
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f(x)= -√x+1
Hero
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domain x >=-1
range y <= 0
rickjbr
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If you take the square root of a negative number, it is not a member of the real number system. x cannot be negative. The domain of f(x) is
\[[0,\infty)\]
Hero
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^not true, x can be negative
rickjbr
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Yes, but it will not yield a real number
rickjbr
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I'm assuming he wants real numbers
Hero
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x + 1 cannot be less than zero
hugsandkisses
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Umm, how about I just post the thing that has all these on them
rickjbr
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It says \[-\sqrt{x}=1\]
rickjbr
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How can x be negative?
Hero
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sqrt(x+1) not sqrt(x)
rickjbr
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Oh i was going by the original post. Didn't see the updated one.
cinar
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\[f(x)=-\sqrt{x+1} \,\,\text {or} f(x)=-\sqrt{x}+1?\]
rickjbr
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That's what I thought cinar
hugsandkisses
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that was a typo. sorry you guys!
rickjbr
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So, which is it?
Hero
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Use parentheses
hugsandkisses
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f(x)= -√x+1
rickjbr
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so 1 is not under the square root?
hugsandkisses
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it is. x+1 are under the square root
rickjbr
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OK, use parentheses next time
\[\sqrt{x+1}>0, x>=-1\]
Domain is \[[-1,\infty)\]
cinar
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then domain is [-1,infinite)
range is [0, infinite)
hugsandkisses
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thank you!