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anonymous

  • 4 years ago

Will give medals Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64? Explain.

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  1. anonymous
    • 4 years ago
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    these are the answers Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64. No. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is not a factor of f(x) = -2x3 + 17x2 - 64. Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64. No. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is not a factor of f(x) = -2x3 + 17x2 - 64.

  2. myininaya
    • 4 years ago
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    x-8=0 => x=8 plug in x=8 and see if you get 0 back

  3. myininaya
    • 4 years ago
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    if you get 0 back then on of the factors are x-8

  4. anonymous
    • 4 years ago
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    Put x=8 in the function or in other words evaluate f(8) if it equates to zero then it is a solution

  5. myininaya
    • 4 years ago
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    if not then one of the factors is not x-8

  6. anonymous
    • 4 years ago
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    so whats the answer ?

  7. myininaya
    • 4 years ago
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    tell me what you get for f(8)

  8. myininaya
    • 4 years ago
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    \[f(8)=-2(8)^3+17(8)^2-64=?\]

  9. anonymous
    • 4 years ago
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    Not not a factor

  10. anonymous
    • 4 years ago
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    i think its d

  11. myininaya
    • 4 years ago
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    you actually don't have to put this in a calculator to check \[f(8)=-2(8)^3+17(8)^2-8^2=8^2(-2(8)+17-1)=8^2(-16+17-1)\]

  12. myininaya
    • 4 years ago
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    is -16+17-1 zero?

  13. anonymous
    • 4 years ago
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    yes

  14. myininaya
    • 4 years ago
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    the answer is then x-8 is a factor of the function

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