anonymous
  • anonymous
Will give medals Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64? Explain.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
these are the answers Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64. No. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is not a factor of f(x) = -2x3 + 17x2 - 64. Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64. No. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is not a factor of f(x) = -2x3 + 17x2 - 64.
myininaya
  • myininaya
x-8=0 => x=8 plug in x=8 and see if you get 0 back
myininaya
  • myininaya
if you get 0 back then on of the factors are x-8

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anonymous
  • anonymous
Put x=8 in the function or in other words evaluate f(8) if it equates to zero then it is a solution
myininaya
  • myininaya
if not then one of the factors is not x-8
anonymous
  • anonymous
so whats the answer ?
myininaya
  • myininaya
tell me what you get for f(8)
myininaya
  • myininaya
\[f(8)=-2(8)^3+17(8)^2-64=?\]
anonymous
  • anonymous
Not not a factor
anonymous
  • anonymous
i think its d
myininaya
  • myininaya
you actually don't have to put this in a calculator to check \[f(8)=-2(8)^3+17(8)^2-8^2=8^2(-2(8)+17-1)=8^2(-16+17-1)\]
myininaya
  • myininaya
is -16+17-1 zero?
anonymous
  • anonymous
yes
myininaya
  • myininaya
the answer is then x-8 is a factor of the function

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