If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 16 ft/sec, its height after t seconds is s(t)=64+16t−16t^2.
what is the maximum height the ball reaches?
What is the velocity of the ball when it hits the ground (height 0)
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hey notsobright can you help me with another one after please
Take derivative and equate it to zero
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what is the slope of the normal line of m2
the equation of the normal lineis y=?
y=10cosx at the point (π/3,5).
derivative of y is -10sinx
The slope of the tangent line is m1 is -10sin(pi/3)
the equation of the tangent line is y= -5sqrt(3)x+(5pi/sqrt3)+5
Rephrase it it is not clear
Find equations of the tangent line and normal line to the curve y=10cosx at the point (π/3,5).
Derivative of y= -10sinx
The slope of the tangent line is m1=-10sin(pi/3)
The equation of the tangent line is y=-5sqrt(3)x+(5pi/sqrt3)+5
The slope of the normal line is m2=?
The equation of the normal line is y=?