If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 16 ft/sec, its height after t seconds is s(t)=64+16t−16t^2.
what is the maximum height the ball reaches?
What is the velocity of the ball when it hits the ground (height 0)

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hey notsobright can you help me with another one after please

Take derivative and equate it to zero
16-32t=0
t=1/2
h=64+ 8-4
h=68

Yeah sure

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