anonymous
  • anonymous
If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 16 ft/sec, its height after t seconds is s(t)=64+16t−16t^2. what is the maximum height the ball reaches? What is the velocity of the ball when it hits the ground (height 0)
Mathematics
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anonymous
  • anonymous
If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 16 ft/sec, its height after t seconds is s(t)=64+16t−16t^2. what is the maximum height the ball reaches? What is the velocity of the ball when it hits the ground (height 0)
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
hey notsobright can you help me with another one after please
anonymous
  • anonymous
Take derivative and equate it to zero 16-32t=0 t=1/2 h=64+ 8-4 h=68
anonymous
  • anonymous
Yeah sure

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anonymous
  • anonymous
ok
anonymous
  • anonymous
what is the slope of the normal line of m2 the equation of the normal lineis y=? y=10cosx at the point (π/3,5). derivative of y is -10sinx The slope of the tangent line is m1 is -10sin(pi/3) the equation of the tangent line is y= -5sqrt(3)x+(5pi/sqrt3)+5
anonymous
  • anonymous
Rephrase it it is not clear
anonymous
  • anonymous
ok
anonymous
  • anonymous
Find equations of the tangent line and normal line to the curve y=10cosx at the point (π/3,5). Derivative of y= -10sinx The slope of the tangent line is m1=-10sin(pi/3) The equation of the tangent line is y=-5sqrt(3)x+(5pi/sqrt3)+5 The slope of the normal line is m2=? The equation of the normal line is y=?

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