anonymous
  • anonymous
(sqrt(x)^2y^4) (3 sqrt(x)^3y^3) (5 sqrt(x)^4)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
could you draw it or type it out in equation form please?
anonymous
  • anonymous
sure, |dw:1328312497394:dw|
anonymous
  • anonymous
xy^2 xy 5root(x^4)

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anonymous
  • anonymous
that's the answer?
anonymous
  • anonymous
oh i mean what would be the exponents of x and y?
anonymous
  • anonymous
well the square root of x^2 is x and the square root of y^4 is 7^2 because you divide by 2 for the cube root its the same thing but you divide by 3 hence the name cube root for the fifthroot you divide by 5 but 4 is not divisible by 5 so it stays under
anonymous
  • anonymous
x^2y^3 and then put the 5root thing beside it |dw:1328313065516:dw|
anonymous
  • anonymous
but say it was the fifth root of x^8, you put the term out and leave whatever the remainder is under so it would be : |dw:1328313159261:dw|
anonymous
  • anonymous
Thankkkk!!
anonymous
  • anonymous
you're welcome

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