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anonymous
 4 years ago
If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 16 ft/sec, its height after t seconds is s(t)=64+16t−16t2.
a) What is the maximum height the ball reaches?
b) What is the velocity of the ball when it hits the ground (height 0)?
anonymous
 4 years ago
If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 16 ft/sec, its height after t seconds is s(t)=64+16t−16t2. a) What is the maximum height the ball reaches? b) What is the velocity of the ball when it hits the ground (height 0)?

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lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2Set the derivative of the equation equal to zero to find the maximum height ds/dt = 1632t= 0 t = 16/32 = .5 seconds substitute that in the equation s=64+16(0.5)16(0.5)^2

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2to find part b you set s(t)=0 then solve the quadratic equation to get two values of t ignore the negative one, then u know that V(t) is derivative of s(t) so u find the derivative and substitute the time u get, to find the velocity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont understand how i should go about solving b

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2first set s(t) =0 so u have 64+16t−16t^2=0 now solve this quadratic equations u will get two solutions for t

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i got 2.5 as the positive solution

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2u should get 7.5 and 0.5 are u sure u did it right?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2\[t=\frac{16 \pm \sqrt{16^24(16)(64)}}{2(16)}\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2re check ur calculations

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.2your positive solution will be 7.5 so usualy if u say s(t) is the displacement the derivative of that is the velocity and the derivative of velocity is acceleration but here we only need the velocity so take the derivative of s(t) V=ds/dt=1632t now substitute the t=7.5 in the above equation u will get V=1632(7.5) And the answer is the velocity u need
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