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anonymous

  • 4 years ago

Plane 1 contains points A(4,3,3) B(6,0,10) C(14,9,3) and plane 2 is given in standard form by -17x - 23y - 5z = -308. 1. Find cos(theta), where theta is an acute angle between the planes

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  1. anonymous
    • 4 years ago
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    here's a pic of the question. the pi looking symbol is just a symbol they use and it doesn't mean anything other than a plane right?

  2. anonymous
    • 4 years ago
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  3. anonymous
    • 4 years ago
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    k i don't understand why i am getting this wrong. you find the equation of the first plane by finding vectors AB and AC, then take the cross product, which i got to be n=<-42,70,42>

  4. anonymous
    • 4 years ago
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    then just use the <-17,-23,5> from the second equation and plug into (a dot b) / mag of a * mag of b = inverse cos to find theta

  5. anonymous
    • 4 years ago
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    which i got to be 114.52 but for some reason it keeps coming up wrong

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