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anonymous
 4 years ago
how do you solve the initial value problem of 4y(3)+2y=0;y(0)=2y(0)=5y(0)=6
anonymous
 4 years ago
how do you solve the initial value problem of 4y(3)+2y=0;y(0)=2y(0)=5y(0)=6

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got the wrong answer :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you retype the question? It didn't come out right? What are those 0s? Are they exponents or numbers?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1What course are studying?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here's is the problem again: 4y'''+2y''=0 y(0)=2 y'(0)=5 y''(0)=6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and im taking differential equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the 3 in the problem represents the third derivative im sorry the original post looks weird

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its supposed to be 4y'''+2y''=0 as in to the third derivative and the second derivative

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1\[4r^3+2r^2=0\]\[2r^2(r+2)=0\]\[r=0,0,1/2\]so \[y=c_1e^{0.5x}+c_2x+c3\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1\[y'=0.5c_1e^{0.5x}+c_2\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1\[y''=0.25c_1e^{0.5x}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i got that but i think i did something wrong after that

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1just plug in the values of x and y, nothing'd go wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did but the answer is wrong! i did y(0)=2=c_1 +c_3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y'(0)=5=c2(1/2)c3e^(1/2x)

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1no the e part cancels coz it equals 1 when x =0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea i know and thats how i solved for c2=12

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1\[y(0)=2\]\[c_1+c_3=2\] \[y'(0)=5\]\[0.5c_1+c_2=5\] \[y''(0)=6\]\[0.25c_1=6\]\[c_1=24\] \[24+c_3=2\]\[c_3=22\]\[0.5(24)+c_2=5\]\[c_2=17\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got c2=7 and thats where i went wrong! thanks soooo much!

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1:D:D its ok, its confusing i know lol, ur welcome

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i frogot .5 was negative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can I ask another question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.08y''+4y'+4y=0, where y(0)=4 and y'(0)=1

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1u want the answers or the whole solution?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but if you cant you can give the answer and I can try to work backwards

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1ok give me 5 min let me work it out

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1\[y=c_1e^{\frac{x}{4}}\cos(\frac{\sqrt 7}{4}x)+c_2e^{\frac{x}{4}}\sin(\frac{\sqrt 7}{4}x)\] i got \[c_1=4\]\[c_2=3.02\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok let me check thanks again

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0woohoooo its correct! thanks sooo much

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i have one last question but if you dont want to do it its totally fine! i had a bunch of roblems to do and these were the three i couldnt get so if its ok can i ask you another one? i feel bad for asking!

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1lol dont feel bad, id love to help, why else would i be on openstudy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0true lol thanks soo much! here is the question:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Find a linear homogeneous constantcoefficient differential equation with the general solution: y(x)=c1e^(2x) + c2Cos(9x) +c3Sin(9x) that has the form y'''+_________y''+_____y'+____y=0 the underscores are supposed to represent blanks lol

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1i got off here by mistake :S let me do it again

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1the solutions are 2,+/9i

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get the solutions?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1do u know how u find the general solution like when u get r=2,3 the general solution is y=c1e^2x+c_2e^3x and when u get complex solutions a+bi and abi the general solution is y=e^ax(c1cos(bx)+c2sin(bx)... u just do it back wards

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok I got it! thnkssss sooo much!!! i really appreciate all yr help!! I also noticed that you joioned 3arabi open stidy group! r u taking arabic classes?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1lol no im half arab :D:D i speak arabic

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh lol I was going to ask if you need any help because I also speak arabic and it's my minor

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1oh wow really :D:D where are u from hehe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm palestinian! hbu?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1o ana kmaaaaaaaaaaaaaan :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but if you're referring to city, I'm from Dearborn lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0omg nooo waaayyy!!! how cool!

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1hehe im from hebron hehe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh by dearborn i meant city in the US haha I'm from beit safafa in palestine

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you live in palestine?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1oh lol i dont know abt US lol, ana 3ayshe bi newzealand

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ooooo keef new zealns? keef al; taqs hunak?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1hehe its summer so yaaaaaaaaay !! :D newzealand btjanen bmoot feha hehe, 3njad sodfe helwee:D:D iza bedik more help ask me :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03njad inti bit mooti feeha? lol hon it's winter bes ana behab al pelletaa3! bhab al thalj! and shukran bes khalasit wajabatee! thanks soo much! i really appreciate your help!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i was supposed to say pelletaa3 not pelletaa3 lol i have no idea hot i typed that instead! lol sorry for the confusion

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0pelletaaaa3 as in winter* i dont know why it keeps sending it as something else

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1if u catch me on here at anytime ill be glad to help u o sara7a u made my day hehe i was a lil upset, bas u made me smile :D hehe Fhemtha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks so much! and same to you! if you have any questions I'll be more than glad to help to the best of my ability! and I'm glad to have made your day! a smile is always better than a frown! :)

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1hehe nice to meet you, esme lana btw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nice to meet you lana! ismee Ranya

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1oooo kman my favorite name ya salam hehe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0btasif bes lazim arooh leana lazam arooh ijeeb igrath min al mahalat! bye! and talk to you soon inshallah! :)Have a great day!! :)

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1:D:D okay take care,, bye byee
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