A ship leaves a pier on a bearing of N50degreeW and travels for 75miles. It turns and sails on a bearing of S 20degree W for 50miles. How far from the pier is the ship?

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A ship leaves a pier on a bearing of N50degreeW and travels for 75miles. It turns and sails on a bearing of S 20degree W for 50miles. How far from the pier is the ship?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Question isnt spelled right its Notical Miles lol :P
But! I guess its like way over 75+50 miles away from that
oh but do you know how to solve this?

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Let me ask my team Srry went to eat Mcdonalds Woot!
|dw:1328342826728:dw| we can solve for x by using law of cosines: The pier, boat, and point where it turned make a triangle of lengths, 75,50,x angle opposite of side x is 70 degrees --> x^2 = 75^2+50^2 -2(75)(50)cos(70) x = 74.564 miles
There we go thanks dumbcow

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