anonymous
  • anonymous
C = 3h - ax a. solve for "h" b. solve for "a" c. solve for "x" I think I got (a.)- C = 3h - ax C + ax = 3h C + ax ------ = h 3 -but for (b.) and (c.), all I've got is: -3h + C = -ax How do I get "a" away from "x", on either problem?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
precal
  • precal
part a is correct
precal
  • precal
for part b divide both sides by -a recall -ax is -a times x the opposite of times is divide
precal
  • precal
sorry my comment is for part c divide both sides by -a for part b divide both sides by x

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So, in the end: (a.) C + ax ------- = h 3 (b.) -3h + C -------- = a -x (c.) -3h + C -------- = x -a Correct?
precal
  • precal
yes
anonymous
  • anonymous
Thank you!
precal
  • precal
Anytime :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.