Can someone please help me find b and c so that the parabola y=-3x^2+bx+c has vertex . (8,4)

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Can someone please help me find b and c so that the parabola y=-3x^2+bx+c has vertex . (8,4)

Mathematics
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Use vertex form and put in the vertex. a = -3
use x = -b/2a
\[y=-3(x-8)^{2}+4\]

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Now rearrange the right side.
so do i just solve for y
\[y=-3(x ^{2}-16x+64)+4=-3x ^{2}-48x-188\]
\[y=-3x ^{2}-48x-188\]
OK, yea it worked for c=-188 but i put in b=-48 and it said inccorect, i was doing it the way you suggested but i cant seem to figure out what b is
Oh gee. -3 (-16x)= POSITIVE 48x Sorry.
yea i just got it, thanks so much
yw
theres also another problem, i think you were actually helping me out with it last week just wondering if you had time to help me again with it cant seem to figure it out

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