Need help in finding the rate of change

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Need help in finding the rate of change

Mathematics
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s(t) = (t - pi / t + 6 pi) ^ 1/3
t = 2pi
srry dont really know how to use the equatio button

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Other answers:

average rate of change over what interval?
it is using derivative to find it
oooooooooooh ok you want the derivative evaluated at \[2\pi\] right?
rate of change is \[\frac{ \Delta s}{\Delta t} = \frac{ds}{dt}\]
\[s(t)=\left (\frac{t-\pi}{t+6\pi}\right) ^{\frac{1}{3}}\] yes?
yess
my teacher didnt use displacement over time...only derivatives
ok so derivative is \[\frac{1}{3}\left( \frac{t-\pi}{t+6\pi}\right)^{-\frac{2}{3}}\times \frac{7\pi}{(x+6\pi)^2}\]
ugly enough. replace x by \[2\pi\] see what you get
ahh..i dont know how to use the equations.. so it is 1/3 ( pi / 8pi ) ^ -2/3 x ( 7 pi / 8pi )^2
i think i get it now thx

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