The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 83 cm, what is the length of the diagonal? Are the two sides x and 2x-2, then multiply them together and equate it to 83. Then solve using quadratic equ. Finally plug it in and use the pythagorean to get the diagonal? Are these the correct steps?

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hey mertsj i think you were helping me with it last week, cant seem to get the correct answer

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\[x(2x-2)=83\]
\[2x^2-2x-83=0\]

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