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anonymous
 4 years ago
The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 83 cm, what is the length of the diagonal? Are the two sides x and 2x2, then multiply them together and equate it to 83. Then solve using quadratic equ. Finally plug it in and use the pythagorean to get the diagonal? Are these the correct steps?
anonymous
 4 years ago
The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 83 cm, what is the length of the diagonal? Are the two sides x and 2x2, then multiply them together and equate it to 83. Then solve using quadratic equ. Finally plug it in and use the pythagorean to get the diagonal? Are these the correct steps?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hey mertsj i think you were helping me with it last week, cant seem to get the correct answer

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[x(2x2)=83\] \[2x^22x83=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea thats what i get so i disregard the negative solution after using the quad equ. and plug my x back into the x and 2x2 right?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Yes those are the correct steps. Are you absolutely certain you have the area right. It is such a weird number and makes the polynomial unfactorable.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea thats what the problem says, ive been doing it like everyday for the past week and keep getting something wrong

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Well double check once again. And I will work through it. We can see if we agree.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is factorable using the quadratic equation

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2So I got the diagonal is 13.80 in decimal form. I will work it out in exact radical form as well.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get the 13.80 because im getting something else. is it \[(2+^{\sqrt{668}})/4\] for x

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Well if the Great Satellite is here, he is undoubtedly correct. I will check my calculations.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for x i get \[\frac{1+\sqrt{167}}{2}\] (via wolfram) and then \[2x2=1+\sqrt{167}2=1+\sqrt{167}\] then again using wolfram i squared and took the square root, but i repeat i make no claim that it is right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you know what the full decimal on that 15.46 answer is b/c i plugged it in and it says its wrong, however sometimes it requires that i write out the entire decimal

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm getting around 13.8064 as well

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i am wrong, mertsj (also quite great i would say) is right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i am as well im going to try it once more and see if i can get another answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The full radical is: \[\frac{\sqrt{6\sqrt{167}140}}{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, it finally took my answer. it was 13.8064 trick was i wasn't able to round it to 13.8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you everybody, i really appreciate the help
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