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anonymous

  • 4 years ago

In a Rhombus, R(1,3) H(6,15) O(?,?) M(14,3) find coordinate O

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  1. Mertsj
    • 4 years ago
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    |dw:1328324270282:dw|

  2. Mertsj
    • 4 years ago
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    To get from R to H go right 5 and up 12. Do the same thing to get from M to O. M is (14,3) right 5 is 19 and up 12 is 15 so point O is (19,15)

  3. anonymous
    • 4 years ago
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    thank you for the response, but i meant mathimatically

  4. Mertsj
    • 4 years ago
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    Slope of RM = 0 Slope of HO = 0 Equation of HO must be y = 15

  5. Mertsj
    • 4 years ago
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    Slope of RH = 12/5. Slope of MO = 12/5 Equation of line through (14,3) with slope 12/5 is 5/12y +51/12=x

  6. Mertsj
    • 4 years ago
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    Find the point of intersection of the two lines y = 15 and x=5/12y+51/4

  7. Mertsj
    • 4 years ago
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    \[x=\frac{5}{12}\times15+\frac{51}{4}=19\] x=19, y = 15 That is point O

  8. anonymous
    • 4 years ago
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    thank you

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