anonymous 4 years ago In a Rhombus, R(1,3) H(6,15) O(?,?) M(14,3) find coordinate O

1. Mertsj

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2. Mertsj

To get from R to H go right 5 and up 12. Do the same thing to get from M to O. M is (14,3) right 5 is 19 and up 12 is 15 so point O is (19,15)

3. anonymous

thank you for the response, but i meant mathimatically

4. Mertsj

Slope of RM = 0 Slope of HO = 0 Equation of HO must be y = 15

5. Mertsj

Slope of RH = 12/5. Slope of MO = 12/5 Equation of line through (14,3) with slope 12/5 is 5/12y +51/12=x

6. Mertsj

Find the point of intersection of the two lines y = 15 and x=5/12y+51/4

7. Mertsj

$x=\frac{5}{12}\times15+\frac{51}{4}=19$ x=19, y = 15 That is point O

8. anonymous

thank you