anonymous
  • anonymous
In a Rhombus, R(1,3) H(6,15) O(?,?) M(14,3) find coordinate O
Mathematics
schrodinger
  • schrodinger
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Mertsj
  • Mertsj
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Mertsj
  • Mertsj
To get from R to H go right 5 and up 12. Do the same thing to get from M to O. M is (14,3) right 5 is 19 and up 12 is 15 so point O is (19,15)
anonymous
  • anonymous
thank you for the response, but i meant mathimatically

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Mertsj
  • Mertsj
Slope of RM = 0 Slope of HO = 0 Equation of HO must be y = 15
Mertsj
  • Mertsj
Slope of RH = 12/5. Slope of MO = 12/5 Equation of line through (14,3) with slope 12/5 is 5/12y +51/12=x
Mertsj
  • Mertsj
Find the point of intersection of the two lines y = 15 and x=5/12y+51/4
Mertsj
  • Mertsj
\[x=\frac{5}{12}\times15+\frac{51}{4}=19\] x=19, y = 15 That is point O
anonymous
  • anonymous
thank you

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