anonymous
  • anonymous
i have 2 equations (4x3+24x2+7x+42)/(x+6)and(2x2+6x+a) the first formula has an x<-6 and the 2nd has x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
factor and cancel to get \[4x^2+7\]
anonymous
  • anonymous
replace x by 6 and get \[4\times 6^2+7=189\]
anonymous
  • anonymous
so my algebra is wrong but my method is right?

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anonymous
  • anonymous
what you then have to do, now that you know the limit of the first expression is equal to 189, is replace x by 6 in the second expression, set it also equal to 189 and solve for "a"
anonymous
  • anonymous
there is only 1 a though
anonymous
  • anonymous
and that is in the 2nd equation
anonymous
  • anonymous
right. the second expression is \[2x^2+6x+a\] and you need to to match up to the first expression when x =6
anonymous
  • anonymous
you know the limit of the first expression at 6 is 186 so write \[2\times 6^2+6\times 6+a=189\] and solve for "a"
anonymous
  • anonymous
sorry i meant "189"
anonymous
  • anonymous
oh ok that makes sense
anonymous
  • anonymous
i get \[108+a=189\] and therefore \[a=81\] but don't take my word for it
anonymous
  • anonymous
it says 81 is in incorrect
anonymous
  • anonymous
x had to equal -6 not 6
anonymous
  • anonymous
x=-7, a=147 x=-8, a=183 and so on

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