i have 2 equations
(4x3+24x2+7x+42)/(x+6)and(2x2+6x+a)
the first formula has an x<-6 and the 2nd has x

Mathematics
i have 2 equations
(4x3+24x2+7x+42)/(x+6)and(2x2+6x+a)
the first formula has an x<-6 and the 2nd has x

Mathematics
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factor and cancel to get
\[4x^2+7\]

replace x by 6 and get
\[4\times 6^2+7=189\]

so my algebra is wrong but my method is right?

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