## anonymous 4 years ago Estimate the wavelength (in nm) of such a proton moving at 2.81x10^8 m/s (mass of a proton = 1.673x10^-27 kg).

To look at a particle as a wave, we need to us the de Broglie equation...$\lambda = \frac{h}{mv}$Where... Lambda is the wavelength. h is Planck's constant m is the mass of the particle, and v is the velocity of the particle This is easy enough. It's already solved for the value we want to find, so we can just plug in some numbers...$\lambda = \frac{6.626*10^{-34}J*s}{(1.673*10^{-27}kg)(2.81*10^{8}m*s^{-1})}$ All of the units cancel appropriately to give us the wavelength in meters...$\lambda = 1.41m*10^{-15}*(\frac{1*10^9nm}{1m})=1.41*10^{-6}nm$