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anonymous

  • 4 years ago

initial value problem -16cos(4t+pi), s'(0)=200, s(0)=0

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  1. dumbcow
    • 4 years ago
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    shouldn't there be a s'(t) somewhere

  2. anonymous
    • 4 years ago
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    its actually d^2s/dt^2=-16cos(4t+pi), s'(0)=200, s(0)=0

  3. anonymous
    • 4 years ago
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    i am having trouble in find the initial value

  4. dumbcow
    • 4 years ago
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    ok so you need to integrate function to find ds/dt, then integrate again to find s(t)

  5. anonymous
    • 4 years ago
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    do i need to find the constant of first inegral before integrating it again?

  6. dumbcow
    • 4 years ago
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    yes, thats where the s'(0)=200 comes in plug in 0 for t and set equal to 200 to solve for contant

  7. anonymous
    • 4 years ago
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    okay, thankyou so much

  8. dumbcow
    • 4 years ago
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    your welcome i get s(t) = cos(4t+pi) +200t +1

  9. anonymous
    • 4 years ago
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    i get s(t)=16cos(4t+pi)+200t+16...:/

  10. dumbcow
    • 4 years ago
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    when integrating you should be dividing coefficient by 4 --> u = 4t+pi du = 4 dt dt = du/4

  11. anonymous
    • 4 years ago
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    oh oh oh.. i totally forgot that, i wasnt even substituting. thankyou soo much.. ur a lifesaver

  12. dumbcow
    • 4 years ago
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    :)

  13. anonymous
    • 4 years ago
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    :D

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