anonymous
  • anonymous
initial value problem -16cos(4t+pi), s'(0)=200, s(0)=0
Mathematics
jamiebookeater
  • jamiebookeater
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dumbcow
  • dumbcow
shouldn't there be a s'(t) somewhere
anonymous
  • anonymous
its actually d^2s/dt^2=-16cos(4t+pi), s'(0)=200, s(0)=0
anonymous
  • anonymous
i am having trouble in find the initial value

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dumbcow
  • dumbcow
ok so you need to integrate function to find ds/dt, then integrate again to find s(t)
anonymous
  • anonymous
do i need to find the constant of first inegral before integrating it again?
dumbcow
  • dumbcow
yes, thats where the s'(0)=200 comes in plug in 0 for t and set equal to 200 to solve for contant
anonymous
  • anonymous
okay, thankyou so much
dumbcow
  • dumbcow
your welcome i get s(t) = cos(4t+pi) +200t +1
anonymous
  • anonymous
i get s(t)=16cos(4t+pi)+200t+16...:/
dumbcow
  • dumbcow
when integrating you should be dividing coefficient by 4 --> u = 4t+pi du = 4 dt dt = du/4
anonymous
  • anonymous
oh oh oh.. i totally forgot that, i wasnt even substituting. thankyou soo much.. ur a lifesaver
dumbcow
  • dumbcow
:)
anonymous
  • anonymous
:D

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