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anonymous
 4 years ago
initial value problem 16cos(4t+pi), s'(0)=200, s(0)=0
anonymous
 4 years ago
initial value problem 16cos(4t+pi), s'(0)=200, s(0)=0

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dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1shouldn't there be a s'(t) somewhere

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its actually d^2s/dt^2=16cos(4t+pi), s'(0)=200, s(0)=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am having trouble in find the initial value

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1ok so you need to integrate function to find ds/dt, then integrate again to find s(t)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do i need to find the constant of first inegral before integrating it again?

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1yes, thats where the s'(0)=200 comes in plug in 0 for t and set equal to 200 to solve for contant

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, thankyou so much

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1your welcome i get s(t) = cos(4t+pi) +200t +1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i get s(t)=16cos(4t+pi)+200t+16...:/

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1when integrating you should be dividing coefficient by 4 > u = 4t+pi du = 4 dt dt = du/4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh oh oh.. i totally forgot that, i wasnt even substituting. thankyou soo much.. ur a lifesaver
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