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wowbriana

  • 3 years ago

how do i simplify 4x^2-7x+3 divided by x^2+5x-6?

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  1. ash2326
    • 3 years ago
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    we have \[\frac{4x^2-7x+3}{x^2-5x+6}\] let's divide (x^2-5x+6)*4=4x^2-20x+24 rewriting the numerator as 4x^2-7x+6=(4x^2-20x+24)+13x-18 so we have now \[\frac{(4x^2-20x+24)+13x-18 }{x^2-5x+6}\] if we simplify we get \[4+\frac{13x-18 }{x^2-5x+6}\]

  2. wowbriana
    • 3 years ago
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    is there more simplifying? because thats not one of my options

  3. wowbriana
    • 3 years ago
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    i wrote the question wrong, the denomenator is supposed to be x^2+5x-6

  4. ash2326
    • 3 years ago
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    then 4(x^2+5x-6)=4x^2+20x-24 so 4x^2-7x+3=(4x^2+20x-24)-27x+27 so we get \[4+\frac{-27x+27}{x^2+5x-6}\]

  5. wowbriana
    • 3 years ago
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    these are my options

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  6. rivermaker
    • 3 years ago
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    \[x^2 + 5x - 6 = (x-1)(x+6)\] \[4x^2-7x+3 = 4x^2-4x-3x+3=4x(x-1)-3(x-1)=(4x-3)(x-1)\] So cancelling (x-1) you can see the answer

  7. wowbriana
    • 3 years ago
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    which answer is it?

  8. rivermaker
    • 3 years ago
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    \[\frac{4x-3}{x+6}\]

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