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anonymous
 4 years ago
Water (2690g ) is heated until it just begins to boil. If the water absorbs 5.31×10^5J of heat in the process, what was the initial temperature of the water?
anonymous
 4 years ago
Water (2690g ) is heated until it just begins to boil. If the water absorbs 5.31×10^5J of heat in the process, what was the initial temperature of the water?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright lets try solving for delta t really quick \[\frac{5.31x10^5}{(2690g)(4.184)}=\Delta T\] let me know what you get.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Did you figure out this one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No i cant im super confused:/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can't divide 5.31x10^5 by 4.184 and then again by 2690?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that will give you the amount that the water changed, but then you have to subtract that from the final temp of the water to get where you started from

Xishem
 4 years ago
Best ResponseYou've already chosen the best response.1What equation are you starting with zbay? I think it's helpful to provide that.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was using q=C *M Delta T but the euation thing isn't loading up
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