Water (2690g ) is heated until it just begins to boil. If the water absorbs 5.31×10^5J of heat in the process, what was the initial temperature of the water?

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Water (2690g ) is heated until it just begins to boil. If the water absorbs 5.31×10^5J of heat in the process, what was the initial temperature of the water?

Chemistry
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alright lets try solving for delta t really quick \[\frac{5.31x10^5}{(2690g)(4.184)}=\Delta T\] let me know what you get.
Did you figure out this one?
No i cant im super confused:/

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you can't divide 5.31x10^5 by 4.184 and then again by 2690?
that will give you the amount that the water changed, but then you have to subtract that from the final temp of the water to get where you started from
What equation are you starting with zbay? I think it's helpful to provide that.
I was using q=C *M Delta T but the euation thing isn't loading up

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