## anonymous 4 years ago Substance/Specific heat capacity silver/0.235 copper/0.385 iron/0.449 aluminum/0.903 ethanol/2.42 water/4.184 An unknown substance has a mass of 10.5g. When the substance absorbs 9.450×10^1 J of heat, the temperature of the substance is raised from 25.0 C to 45.0C. What is the most likely identity of the substance?

$Q=cm \Delta T \rightarrow c=\frac{Q}{m \Delta T}$$c=\frac{9.450*10^1J}{(10.5g)(20.0C)}=.450\frac{J}{g*C}$This specific heat capacity most closely resembles that of iron's.