AravindG
  • AravindG
doubts on newton laws of motion
Physics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
AravindG
  • AravindG
k thx for cming
AravindG
  • AravindG
how many types of inertia are there?
AravindG
  • AravindG
easmore?

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anonymous
  • anonymous
Typically, we consider two. That associated with linear motion and that associated with rotational motion.
AravindG
  • AravindG
oh i was asking like inertia of rest ,inertia of motion,inertia of direction etc
anonymous
  • anonymous
They are all the same. Inertia is simply a measure of how an object resists a change in motion.
AravindG
  • AravindG
hmm. can u xplain inertia of direction and based on tht reason this: wheels of vehicles are provided with mudguards
anonymous
  • anonymous
The mud has a tendency to always maintain the same direction of travel. Eventually, this tendency exceeds the forces acting on the mud by the tire. When this happens, the mud will leave the tire in a tangential manner.
AravindG
  • AravindG
doubt 2:a body of mass 2kg moves with an acceleration of 3 m/s^2 find change in momentum in in one second
AravindG
  • AravindG
y is it the answer force ma?
anonymous
  • anonymous
That is the definition of Newton's Second Law. \[F = {d \vec p \over dt}\]
AravindG
  • AravindG
doubt 3:what is average force?
anonymous
  • anonymous
\[F_{avg} = {\Delta \vec p \over \Delta t}\]
AravindG
  • AravindG
doubt 4:A shell explodes in mid air into 2 equal fragments.what is direction of motion of 2 particles .explain this
anonymous
  • anonymous
This is a result of internal forces only. Since Newton's Second Law considers only external forces, there are couple inferences we can draw. Let's assume the shell is at rest when it explodes. First, the center of mass of the two particles will remain at the same point in space. Second, the net momentum of the two particles will equal zero (because the object is initially at rest).
AravindG
  • AravindG
can u xplain more i am cnfused
anonymous
  • anonymous
The exact direction and nature of the motion of the two particles after the explosion is dependent on the nature of the explosion force.
AravindG
  • AravindG
hw can we make such an assumption
AravindG
  • AravindG
y dont we consider gravity as external force?
AravindG
  • AravindG
?
anonymous
  • anonymous
Gravity can be considered. The center of mass of the two particles will follow the path prescribed by the external forces.
anonymous
  • anonymous
This is definitely classical mechanics.
AravindG
  • AravindG
eashmore?
anonymous
  • anonymous
Yes?
AravindG
  • AravindG
xplain
anonymous
  • anonymous
What are you confused about?
anonymous
  • anonymous
Let's keep things simple for now. Air resistance will change things.
AravindG
  • AravindG
wel wat is direction of motion
anonymous
  • anonymous
The motion of the individual particles is dependent on the nature of the explosion. The center of mass however, will have motion as described by external forces.
AravindG
  • AravindG
my text says they move in opp directions
AravindG
  • AravindG
for cinservation of momentum
anonymous
  • anonymous
Their net momentum after the explosion must equal the momentum of the shell before explosion. Because momentum is a vector quantity, they will travel away from each other (i.e. their velocities will have opposite signs).
AravindG
  • AravindG
we assume it was at rest??
anonymous
  • anonymous
Let's take the simplest example. Take the shell to be on the ground, which is smooth. After the explosion the net momentum will be zero.
AravindG
  • AravindG
mth3v4 pls dont mess around
anonymous
  • anonymous
If the shell is in motion. The net momentum of the two particles will equal the momentum of the shell before the explosion.
AravindG
  • AravindG
k
AravindG
  • AravindG
hw do we recognize an internal force ?? u see i am vonfused with that
anonymous
  • anonymous
I already established this as being classical mechanics. Please don't comment if you don't have anything valuable to add.
anonymous
  • anonymous
I don't understand the question Aravind
AravindG
  • AravindG
wel u see an example like i hav a fan kept in a boat
AravindG
  • AravindG
then i turn the fan on facing the sail
anonymous
  • anonymous
Nvm. I understand. An internal force is one that does not mechanical energy of a system.
AravindG
  • AravindG
the boat doesnt move
anonymous
  • anonymous
An internal force is one that does not change the mechanical energy of a system.
AravindG
  • AravindG
hw do we recognize that . u seei thought he wind from fan can move the boat
anonymous
  • anonymous
Newton's Third Law. The fan pushes the wind against the sail, but the wind pushes back on the fan. Since the fan and sail are coupled by the boat, the boat doesn't move.
AravindG
  • AravindG
ya u r spam
AravindG
  • AravindG
can u show a fig
AravindG
  • AravindG
eashmore?
anonymous
  • anonymous
|dw:1328338036916:dw|
AravindG
  • AravindG
hw can wind return to fan??
anonymous
  • anonymous
Those are forces. The square below represents the boat system. There are not external forces. |dw:1328338113551:dw|
AravindG
  • AravindG
srry easmore bt i am not getting u
AravindG
  • AravindG
:(
AravindG
  • AravindG
i dont understand hww a return force acts on fan
anonymous
  • anonymous
Do you doubt the existence of the return force or what causes the return force?
anonymous
  • anonymous
Instead of a fan. Let's say you push directly on the sail mast. In this case, would the boat move?
anonymous
  • anonymous
I have to leave soon.
AravindG
  • AravindG
hey gogind can we cntinu with this discussion?
AravindG
  • AravindG
k pls xplain
anonymous
  • anonymous
hmm..lets see...You are having trouble with imagining the force that is acting on the fan, correct?
AravindG
  • AravindG
ys
anonymous
  • anonymous
Try imagine in like this. Fan pushes a bunch of molecules to the sail of the boat (we call that wind) , but since all these little molecules have some mass, newtons 3rd laws says that: As the blade of the fan exerts force on the molecules, all those molecules must exert the same force on the blade but it in opposite direction. OK! So now there is a bunch of molecules traveling towards the sail and eventually hitting it. When they hit the sail the same thing happens, they exert force on the sail, and since the sail is connected to the boat, they actually exert in on the boat. So in conclusion: The boat wants to go backwards, because of the force molecules exert on the blade of the fan which is connected to the boat, but the same molecules hit the sail which is also connected to the boat, causing the boat wanting to go forward. So the net result of this two forces is 0, because they have the same magnitude but opposite direction. What do you think would happen if there was no sail?
AravindG
  • AravindG
hmmm..it would have remained in rest
AravindG
  • AravindG
isnt it?
anonymous
  • anonymous
if there IS a sail it would remain at rest, because the forces cancel each other. If there were NO sail at all, the boat would travel backwards. In the boat with no sail, molecules that acted on the blade of the fan would just travel in the opposite direction of the boat with nothing to stop them (no sail), so the only force that is acting on the boat is the one acting on the fan, since there is not force to cancel in out the boat would move backwards.
AravindG
  • AravindG
k i understood
AravindG
  • AravindG
but is it sure that alll molecules from fan would hit the sail??
anonymous
  • anonymous
of course not. What we are talking about here is the ideal situation. In real life a good part of molecules would not hit sail. Imagine you had a really small sail and a huge fan, some molecules would hit the sail but a bigger part of them would not. So the net effect would be that you are moving backwards. In this case the force acting on the blades is much garter then the one acting on the sail...
AravindG
  • AravindG
k i understood it cmpletely thx
AravindG
  • AravindG
i hav some othr doubts too can u help?
anonymous
  • anonymous
I don't have time, since I'm studying right now. Just post the question in the group and someone will answer, if they don't I'll answer later if I can
AravindG
  • AravindG
wen will u be free?
anonymous
  • anonymous
I don't know, when I get tired i guess :D. Just post on the group I'm sure someone will take a look at it
anonymous
  • anonymous
what doubts??

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