## anonymous 4 years ago What was the mass of the piece of copper? A piece of copper metal (specific heat 0.385J/g degree C ) at 86.5degree C is placed in 50.0g of water at 16.4 degree C. The metal and water come to the same temperature of 23.9 degreeC

First, we need to find the amount of heat energy that the water absorbed. This will tell us (assuming that these conditions are ideal; no heat loss, etc.) how much the copper released. So, using...$Q=cm \Delta T$$Q=(4.186\frac{J}{g*C})(50.0g)(23.9C-16.4C)=1569.75J$Now, we assume that ALL energy that the water gained was gained from the copper...$Q=cm \Delta T \rightarrow m=\frac{Q}{c \Delta T}$$m=\frac{-1569.75J}{(0.385\frac{J}{g*C})(16.4C-86.5C)}=58.1636623g$And with the proper number of SFs...$58.2g$